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Find the area of a parallelogram whose base length is 14 cm and height is 11 cm.

Complete the following table:

\begin{tabular}{|l|l|l|l|}
\hline
\begin{tabular}{l}
Base \\ length
\end{tabular} & Height & \begin{tabular}{l}
Area in square \\ meters
\end{tabular} \\
\hline
700 m & 40 m & \\
\hline
800 m & 120 m & \\
\hline
580 m & 100 m & \\
\hline
1300 m & 600 m & \\
\hline
\end{tabular}

Leila's garden is in the shape of a parallelogram. The length of the base is 32 m and its height is 21 m. Find the area of the garden.

Sagot :

GinnyAnswer
To solve these problems, let's break them down into parts:

1. Area of a Parallelogram Based on Given Base and Height:
- Formula for the Area of a Parallelogram:
[tex]\[ \text{Area} = \text{Base} \times \text{Height} \][/tex]
- Given Measurements:
- Base length [tex]\( = 14 \text{ cm} \)[/tex]
- Height [tex]\( = 11 \text{ cm} \)[/tex]
- Calculation:
[tex]\[ \text{Area} = 14 \times 11 = 154 \text{ square centimeters (cm}^2\text{)} \][/tex]

2. Complete the Given Table:
- Formula for the Area of a Parallelogram:
[tex]\[ \text{Area} = \text{Base} \times \text{Height} \][/tex]
- Using the formula, we fill in each row of the table:
- For base [tex]\( = 700 \text{ m} \)[/tex] and height [tex]\( = 40 \text{ m} \)[/tex]:
[tex]\[ \text{Area} = 700 \times 40 = 28000 \text{ square meters (m}^2\text{)} \][/tex]
- For base [tex]\( = 800 \text{ m} \)[/tex] and height [tex]\( = 120 \text{ m} \)[/tex]:
[tex]\[ \text{Area} = 800 \times 120 = 96000 \text{ square meters (m}^2\text{)} \][/tex]
- For base [tex]\( = 580 \text{ m} \)[/tex] and height [tex]\( = 100 \text{ m} \)[/tex]:
[tex]\[ \text{Area} = 580 \times 100 = 58000 \text{ square meters (m}^2\text{)} \][/tex]
- For base [tex]\( = 1300 \text{ m} \)[/tex] and height [tex]\( = 600 \text{ m} \)[/tex]:
[tex]\[ \text{Area} = 1300 \times 600 = 780000 \text{ square meters (m}^2\text{)} \][/tex]

Now the completed table looks like this:
[tex]\[ \begin{tabular}{|l|l|l|} \hline Base length (m) & Height (m) & Area in square meters \\ \hline 700 & 40 & 28000 \\ \hline 800 & 120 & 96000 \\ \hline 580 & 100 & 58000 \\ \hline 1300 & 600 & 780000 \\ \hline \end{tabular} \][/tex]

3. Area of Leli's Garden:
- Given Measurements:
- Base length [tex]\( = 32 \text{ m} \)[/tex]
- Height [tex]\( = 21 \text{ m} \)[/tex]
- Calculation:
[tex]\[ \text{Area} = 32 \times 21 = 672 \text{ square meters (m}^2\text{)} \][/tex]

So, the final results are:
- The area of a parallelogram with base length 14 cm and height 11 cm is 154 cm².
- The completed table with areas in square meters is as shown.
- The area of Leli's garden, with dimensions 32 m by 21 m, is 672 m².
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