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Which of the following are the factors of [tex]$4b^2 - 16$[/tex]?

A. [tex]$(2b - 2)(2b + 4)$[/tex]

B. [tex][tex]$(2b + 4)(2b + 4)$[/tex][/tex]

C. [tex]$2(b - 4)(b + 4)$[/tex]

D. [tex]$4(b - 2)(b + 2)$[/tex]


Sagot :

To solve the problem of finding the factors of [tex]\(4b^2 - 16\)[/tex], we can follow these steps:

1. Identify the given expression:
The expression to be factored is [tex]\(4b^2 - 16\)[/tex].

2. Factor out the greatest common factor (GCF):
Both terms [tex]\(4b^2\)[/tex] and [tex]\(-16\)[/tex] are divisible by 4. Thus, we factor out 4:
[tex]\[ 4b^2 - 16 = 4(b^2 - 4) \][/tex]

3. Factor the quadratic expression inside the parentheses:
The expression [tex]\(b^2 - 4\)[/tex] is a difference of squares, which can be factored using the formula [tex]\(a^2 - b^2 = (a-b)(a+b)\)[/tex]. Here, [tex]\(b^2 - 4\)[/tex] is of the form [tex]\(a^2 - b^2\)[/tex] with [tex]\(a = b\)[/tex] and [tex]\(b = 2\)[/tex]:
[tex]\[ b^2 - 4 = (b - 2)(b + 2) \][/tex]

4. Combine the factors:
Substitute back the factors into the original factored expression:
[tex]\[ 4(b^2 - 4) = 4(b - 2)(b + 2) \][/tex]

Thus, the factors of [tex]\(4b^2 - 16\)[/tex] are [tex]\(4(b - 2)(b + 2)\)[/tex].

Given the options:
A. [tex]\((2b - 2)(2b + 4)\)[/tex]
B. [tex]\((2b + 4)(2b + 4)\)[/tex]
C. [tex]\(2(b - 4)(b + 4)\)[/tex]
D. [tex]\(4(b - 2)(b + 2)\)[/tex]

The correct answer is D. [tex]\(4(b - 2)(b + 2)\)[/tex].