Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Problem 2

Simplify the following expression:

[tex]\[ \frac{x^2 + 6x - 7}{x^2 - 36} \cdot \frac{x^2 - 2x - 24}{2x^2 + 8x - 42} \][/tex]

Answer:

[tex]\[ \frac{(x-1)(x+4)}{2(x-3)(x+6)} \][/tex]


Sagot :

Let's simplify the given expression step-by-step.

The given expression is:
[tex]\[ \frac{x^2 + 6x - 7}{x^2 - 36} \cdot \frac{x^2 - 2x - 24}{2x^2 + 8x - 42} \][/tex]

1. Factorize each expression in the numerator and the denominator:

- Factorizing [tex]\( x^2 + 6x - 7 \)[/tex]:
[tex]\[ x^2 + 6x - 7 = (x + 7)(x - 1) \][/tex]

- Factorizing [tex]\( x^2 - 36 \)[/tex] (Difference of squares):
[tex]\[ x^2 - 36 = (x + 6)(x - 6) \][/tex]

- Factorizing [tex]\( x^2 - 2x - 24 \)[/tex]:
[tex]\[ x^2 - 2x - 24 = (x - 6)(x + 4) \][/tex]

- Factorizing [tex]\( 2x^2 + 8x - 42 \)[/tex]:
First, factor out the common factor of 2:
[tex]\[ 2x^2 + 8x - 42 = 2(x^2 + 4x - 21) \][/tex]
Now factorize [tex]\( x^2 + 4x - 21 \)[/tex]:
[tex]\[ x^2 + 4x - 21 = (x + 7)(x - 3) \][/tex]
Therefore,
[tex]\[ 2x^2 + 8x - 42 = 2(x + 7)(x - 3) \][/tex]

2. Rewrite the original expression with the factors:
[tex]\[ \frac{(x + 7)(x - 1)}{(x + 6)(x - 6)} \cdot \frac{(x - 6)(x + 4)}{2(x + 7)(x - 3)} \][/tex]

3. Simplify by canceling common factors:
- [tex]\( (x + 7) \)[/tex] in the numerator and denominator
- [tex]\( (x - 6) \)[/tex] in the numerator and denominator

The expression simplifies to:
[tex]\[ \frac{(x - 1)(x + 4)}{(x + 6)} \cdot \frac{1}{2(x - 3)} \][/tex]

This can be simplified further by multiplying:
[tex]\[ \frac{(x - 1)(x + 4)}{2(x + 6)(x - 3)} \][/tex]

So, the simplified expression is:
[tex]\[ \frac{(x - 1)(x + 4)}{2(x + 6)(x - 3)} \][/tex]