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Problem: [tex]\(\frac{4 x^2 y^7}{32 x^4 y^3} \cdot \frac{16 x^2}{8 y^6}\)[/tex]

Simplify the expression.


Sagot :

Let's simplify the given expression step-by-step:

[tex]\[ \frac{4 x^2 y^7}{32 x^4 y^3} \cdot \frac{16 x^2}{8 y^6} \][/tex]

Step 1: Simplify the first fraction [tex]\(\frac{4 x^2 y^7}{32 x^4 y^3}\)[/tex]

- Simplify the coefficients:
[tex]\[ \frac{4}{32} = \frac{1}{8} \][/tex]

- Simplify the [tex]\(x\)[/tex]-terms:
[tex]\[ \frac{x^2}{x^4} = x^{2-4} = x^{-2} \][/tex]

- Simplify the [tex]\(y\)[/tex]-terms:
[tex]\[ \frac{y^7}{y^3} = y^{7-3} = y^4 \][/tex]

So, the first fraction simplifies to:
[tex]\[ \frac{1}{8} \cdot x^{-2} \cdot y^4 = \frac{y^4}{8 x^2} \][/tex]

Step 2: Simplify the second fraction [tex]\(\frac{16 x^2}{8 y^6}\)[/tex]

- Simplify the coefficients:
[tex]\[ \frac{16}{8} = 2 \][/tex]

- Simplify the [tex]\(x\)[/tex]-terms:
[tex]\[ x^2 \text{ (remains as is)} \][/tex]

- Simplify the [tex]\(y\)[/tex]-terms:
[tex]\[ \frac{1}{y^6} = y^{-6} \][/tex]

So, the second fraction simplifies to:
[tex]\[ 2 \cdot x^2 \cdot y^{-6} = \frac{2 x^2}{y^6} \][/tex]

Step 3: Multiply the simplified fractions together:

[tex]\[ \frac{y^4}{8 x^2} \cdot \frac{2 x^2}{y^6} \][/tex]

Now we simplify this product as follows:

- Simplify the coefficients:
[tex]\[ \frac{1}{8} \cdot 2 = \frac{2}{8} = \frac{1}{4} \][/tex]

- Simplify the [tex]\(x\)[/tex]-terms:
[tex]\[ x^{-2} \cdot x^2 = x^{-2+2} = x^0 = 1 \][/tex]

- Simplify the [tex]\(y\)[/tex]-terms:
[tex]\[ y^4 \cdot y^{-6} = y^{4-6} = y^{-2} = \frac{1}{y^2} \][/tex]

Putting it all together:

[tex]\[ \frac{1}{4} \cdot 1 \cdot \frac{1}{y^2} = \frac{1}{4 y^2} \][/tex]

Thus, the simplified expression is:

[tex]\[ \boxed{\frac{1}{4 y^2}} \][/tex]