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Sagot :
To solve the given logarithmic equation [tex]\(\log_{36} x = \frac{1}{2}\)[/tex], we need to convert it into its exponential form. A logarithmic equation [tex]\(\log_b a = c\)[/tex] is equivalent to the exponential equation [tex]\(b^c = a\)[/tex].
Given the equation:
[tex]\[ \log_{36} x = \frac{1}{2} \][/tex]
We can rewrite this in its exponential form:
[tex]\[ 36^{\frac{1}{2}} = x \][/tex]
Next, we simplify the expression [tex]\(36^{\frac{1}{2}}\)[/tex]. The expression [tex]\(36^{\frac{1}{2}}\)[/tex] represents the square root of 36. Therefore,
[tex]\[ 36^{\frac{1}{2}} = \sqrt{36} \][/tex]
We know that the square root of 36 is 6:
[tex]\[ \sqrt{36} = 6 \][/tex]
Thus, we have:
[tex]\[ x = 6 \][/tex]
Therefore, the solution to the equation [tex]\(\log_{36} x = \frac{1}{2}\)[/tex] is:
[tex]\[ x = 6 \][/tex]
Given the equation:
[tex]\[ \log_{36} x = \frac{1}{2} \][/tex]
We can rewrite this in its exponential form:
[tex]\[ 36^{\frac{1}{2}} = x \][/tex]
Next, we simplify the expression [tex]\(36^{\frac{1}{2}}\)[/tex]. The expression [tex]\(36^{\frac{1}{2}}\)[/tex] represents the square root of 36. Therefore,
[tex]\[ 36^{\frac{1}{2}} = \sqrt{36} \][/tex]
We know that the square root of 36 is 6:
[tex]\[ \sqrt{36} = 6 \][/tex]
Thus, we have:
[tex]\[ x = 6 \][/tex]
Therefore, the solution to the equation [tex]\(\log_{36} x = \frac{1}{2}\)[/tex] is:
[tex]\[ x = 6 \][/tex]
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