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Given a test to a group of students, the grades and gender are summarized below:

\begin{tabular}{|r|r|r|r|r|}
\hline & A & B & C & Total \\
\hline Male & 4 & 16 & 17 & 37 \\
\hline Female & 3 & 19 & 12 & 34 \\
\hline Total & 7 & 35 & 29 & 71 \\
\hline
\end{tabular}

If one student is chosen at random, find the probability that the student was female OR got a "B".

Sagot :

To find the probability that a randomly chosen student was either female or got a "B" grade, we need to count the total number of students who meet at least one of these criteria and then divide by the total number of students.

Here's a step-by-step solution:

1. Total number of students: According to the table, the total number of students is 71.

2. Total number of females: There are 34 female students.

3. Total number of "B" grades: There are 35 students who received a "B" grade.

4. Number of females who received a "B": From the table, we see that there are 19 female students who received a "B" grade.

5. Using the principle of inclusion and exclusion: To avoid double-counting students who are both female and received a "B" grade, we use the following formula:
[tex]\[ \text{Total females or B} = (\text{Total females}) + (\text{Total B grades}) - (\text{Number of females who received a B}) \][/tex]
Plugging in the numbers:
[tex]\[ \text{Total females or B} = 34 + 35 - 19 = 50 \][/tex]

6. Calculate the probability: The probability is determined by dividing the total number of students who are either female or received a "B" by the total number of students:
[tex]\[ \text{Probability} = \frac{\text{Total females or B}}{\text{Total students}} = \frac{50}{71} \][/tex]

7. Simplify the result: The probability as a decimal is approximately 0.7042.

So, the probability that a randomly chosen student was either female or received a "B" grade is [tex]\( \frac{50}{71} \)[/tex] or approximately 0.7042.
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