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Sagot :
To determine the probability that a randomly chosen student from this group received either an A or a B on the test, follow these steps:
1. Identify and sum the total number of students who received an A.
2. Identify and sum the total number of students who received a B.
3. Add these two sums together to get the number of students who received either an A or a B.
4. Divide the number of students who received an A or a B by the total number of students to find the probability.
Given data:
- Total number of students: [tex]\( 62 \)[/tex]
- Number of students who got an A: [tex]\( 22 \)[/tex]
- Number of students who got a B: [tex]\( 27 \)[/tex]
Step-by-step solution:
1. Number of students who got an A: [tex]\( 22 \)[/tex]
2. Number of students who got a B: [tex]\( 27 \)[/tex]
3. Number of students who got either an A or a B:
[tex]\[ 22 + 27 = 49 \][/tex]
4. Probability of a student getting an A or a B:
[tex]\[ \frac{\text{Number of students who got either an A or a B}}{\text{Total number of students}} = \frac{49}{62} \][/tex]
So, the probability that a randomly chosen student got an A or a B is:
[tex]\[ P(A \text { or } B) = \frac{49}{62} \][/tex]
1. Identify and sum the total number of students who received an A.
2. Identify and sum the total number of students who received a B.
3. Add these two sums together to get the number of students who received either an A or a B.
4. Divide the number of students who received an A or a B by the total number of students to find the probability.
Given data:
- Total number of students: [tex]\( 62 \)[/tex]
- Number of students who got an A: [tex]\( 22 \)[/tex]
- Number of students who got a B: [tex]\( 27 \)[/tex]
Step-by-step solution:
1. Number of students who got an A: [tex]\( 22 \)[/tex]
2. Number of students who got a B: [tex]\( 27 \)[/tex]
3. Number of students who got either an A or a B:
[tex]\[ 22 + 27 = 49 \][/tex]
4. Probability of a student getting an A or a B:
[tex]\[ \frac{\text{Number of students who got either an A or a B}}{\text{Total number of students}} = \frac{49}{62} \][/tex]
So, the probability that a randomly chosen student got an A or a B is:
[tex]\[ P(A \text { or } B) = \frac{49}{62} \][/tex]
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