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Each day that a library book is kept past its due date, a [tex]$\$[/tex]0.30[tex]$ fee is charged at midnight. Which ordered pair is a viable solution if $[/tex]x[tex]$ represents the number of days that a library book is late and $[/tex]y[tex]$ represents the total fee?

A. $[/tex](-3, -0.90)[tex]$
B. $[/tex](-2.5, -0.75)[tex]$
C. $[/tex](4.5, 1.35)[tex]$
D. $[/tex](8, 2.40)$

Sagot :

To determine which ordered pair [tex]\((x, y)\)[/tex] is a viable solution, we need to check if the given fee per day and the total fee match. Here, [tex]\(x\)[/tex] represents the number of days a book is late and [tex]\(y\)[/tex] represents the total fee. The daily fee is \$0.30.

Let's evaluate each ordered pair:

1. For [tex]\((-3, -0.90)\)[/tex]:
[tex]\[ \text{Total fee} = 0.30 \times (-3) = -0.90 \][/tex]
The calculated total fee is [tex]\(-0.90\)[/tex], which matches the given [tex]\(y\)[/tex] value in the ordered pair. Therefore, [tex]\((-3, -0.90)\)[/tex] is a viable solution.

2. For [tex]\((-2.5, -0.75)\)[/tex]:
[tex]\[ \text{Total fee} = 0.30 \times (-2.5) = -0.75 \][/tex]
The calculated total fee is [tex]\(-0.75\)[/tex], which matches the given [tex]\(y\)[/tex] value in the ordered pair. Therefore, [tex]\((-2.5, -0.75)\)[/tex] is a viable solution.

3. For [tex]\((4.5, 1.35)\)[/tex]:
[tex]\[ \text{Total fee} = 0.30 \times 4.5 = 1.35 \][/tex]
The calculated total fee is [tex]\(1.35\)[/tex], which matches the given [tex]\(y\)[/tex] value in the ordered pair. Therefore, [tex]\((4.5, 1.35)\)[/tex] is a viable solution.

4. For [tex]\((8, 2.40)\)[/tex]:
[tex]\[ \text{Total fee} = 0.30 \times 8 = 2.40 \][/tex]
The calculated total fee is [tex]\(2.40\)[/tex], which matches the given [tex]\(y\)[/tex] value in the ordered pair. Therefore, [tex]\((8, 2.40)\)[/tex] is a viable solution.

Based on the calculations, the viable solutions are:

- [tex]\((-2.5, -0.75)\)[/tex]
- [tex]\((8, 2.40)\)[/tex]
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