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Question 8 (3 marks)

The course for a yacht race starts from point A. The first section is due south for a distance of 18 kilometres to point B. The second section is on a bearing of 160° for a distance of 12 kilometres to point C. The third and final section is a straight line from point C to point A.

(a) Draw a sketch showing the above information.

Sagot :

Let's begin by visualizing the information given in the problem through a sketch. We'll outline the steps needed to draw the sketch of the course followed by the yacht.

1. Point A: Start with point A, which will be the origin (0, 0) on our coordinate system.

2. Point B: The first section is due south for 18 kilometers. Since south is straight down on the coordinate plane, point B will be directly below point A. Therefore, it will have coordinates (0, -18).

3. Point C: For the second section, we'll determine the coordinates of point C based on a bearing of 160° from point B for a distance of 12 kilometers.

- The bearing of 160° is measured clockwise from the north direction.
- We can find the position of point C using this bearing and distance, and we find that point C has coordinates (4.10, -29.28).

Now that we have the coordinates, we can draw the sketch:

- Step 1: Draw point A at the origin (0, 0).
- Step 2: From point A, draw a straight line going downward (south) to point B, which is at (0, -18). Label this point B.
- Step 3: Point C is calculated at coordinates (4.10, -29.28). From point B, draw a line at an angle representing the bearing of 160°, ending at point C with the mentioned coordinates. Label this point C accordingly.
- Step 4: Finally, connect point C back to point A with a straight line, completing the triangle.

### Sketch description:
- A: at (0, 0)
- B: at (0, -18)
- C: at (4.10, -29.28)

```
A (0, 0)
|
|
|
| B (0, -18)
|
/
/
C (4.10, -29.28)
```

This completes the visual representation of the yacht's course based on the given information.