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To identify the reflection of [tex]\( f(x) = \sqrt{x} \)[/tex] over the [tex]\( x \)[/tex]-axis, it's essential to determine the reflected points of [tex]\( f(x) \)[/tex].
Recall that reflecting a function [tex]\( f(x) \)[/tex] over the [tex]\( x \)[/tex]-axis transforms [tex]\( f(x) \)[/tex] to [tex]\( -f(x) \)[/tex]. This means that for every point [tex]\( (x, f(x)) \)[/tex] on the graph of [tex]\( f(x) \)[/tex], the corresponding point on the reflected graph is [tex]\( (x, -f(x)) \)[/tex].
Given the values of [tex]\( f(x) \)[/tex] in the table:
[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -1 & \text{undefined} \\ \hline 0 & 0 \\ \hline 1 & 1 \\ \hline 4 & 2 \\ \hline \end{array} \][/tex]
We reflect each defined point over the [tex]\( x \)[/tex]-axis:
1. For [tex]\( x = 0 \)[/tex], [tex]\( f(0) = 0 \)[/tex]. Its reflection is [tex]\( (0, -0) = (0, 0) \)[/tex].
2. For [tex]\( x = 1 \)[/tex], [tex]\( f(1) = 1 \)[/tex]. Its reflection is [tex]\( (1, -1) \)[/tex].
3. For [tex]\( x = 4 \)[/tex], [tex]\( f(4) = 2 \)[/tex]. Its reflection is [tex]\( (4, -2) \)[/tex].
Summarizing these reflections:
[tex]\[ \begin{array}{|c|c|} \hline x & -f(x) \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline 4 & -2 \\ \hline \end{array} \][/tex]
Therefore, the reflected values of [tex]\( f(x) = \sqrt{x} \)[/tex] over the [tex]\( x \)[/tex]-axis are:
[tex]\[ \begin{array}{|c|c|} \hline x & y = -f(x) \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline 4 & -2 \\ \hline \end{array} \][/tex]
These reflect the points correctly as [tex]\( (0, 0) \)[/tex], [tex]\( (1, -1) \)[/tex], and [tex]\( (4, -2) \)[/tex].
So, the correct representation of the reflection over the [tex]\( x \)[/tex]-axis in the given tabular format would be:
[tex]\[ \begin{array}{|c|c|} \hline x & y = -f(x) \\ \hline -1 & \text{undefined} \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline 4 & -2 \\ \hline \end{array} \][/tex]
These values match the result for the reflected points as calculated.
Recall that reflecting a function [tex]\( f(x) \)[/tex] over the [tex]\( x \)[/tex]-axis transforms [tex]\( f(x) \)[/tex] to [tex]\( -f(x) \)[/tex]. This means that for every point [tex]\( (x, f(x)) \)[/tex] on the graph of [tex]\( f(x) \)[/tex], the corresponding point on the reflected graph is [tex]\( (x, -f(x)) \)[/tex].
Given the values of [tex]\( f(x) \)[/tex] in the table:
[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -1 & \text{undefined} \\ \hline 0 & 0 \\ \hline 1 & 1 \\ \hline 4 & 2 \\ \hline \end{array} \][/tex]
We reflect each defined point over the [tex]\( x \)[/tex]-axis:
1. For [tex]\( x = 0 \)[/tex], [tex]\( f(0) = 0 \)[/tex]. Its reflection is [tex]\( (0, -0) = (0, 0) \)[/tex].
2. For [tex]\( x = 1 \)[/tex], [tex]\( f(1) = 1 \)[/tex]. Its reflection is [tex]\( (1, -1) \)[/tex].
3. For [tex]\( x = 4 \)[/tex], [tex]\( f(4) = 2 \)[/tex]. Its reflection is [tex]\( (4, -2) \)[/tex].
Summarizing these reflections:
[tex]\[ \begin{array}{|c|c|} \hline x & -f(x) \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline 4 & -2 \\ \hline \end{array} \][/tex]
Therefore, the reflected values of [tex]\( f(x) = \sqrt{x} \)[/tex] over the [tex]\( x \)[/tex]-axis are:
[tex]\[ \begin{array}{|c|c|} \hline x & y = -f(x) \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline 4 & -2 \\ \hline \end{array} \][/tex]
These reflect the points correctly as [tex]\( (0, 0) \)[/tex], [tex]\( (1, -1) \)[/tex], and [tex]\( (4, -2) \)[/tex].
So, the correct representation of the reflection over the [tex]\( x \)[/tex]-axis in the given tabular format would be:
[tex]\[ \begin{array}{|c|c|} \hline x & y = -f(x) \\ \hline -1 & \text{undefined} \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline 4 & -2 \\ \hline \end{array} \][/tex]
These values match the result for the reflected points as calculated.
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