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Sagot :
To determine the order of the circuits by decreasing current, we need to calculate the current in each circuit using Ohm's Law, which is given by the formula:
[tex]\[ I = \frac{V}{R} \][/tex]
where [tex]\( I \)[/tex] is the current, [tex]\( V \)[/tex] is the voltage, and [tex]\( R \)[/tex] is the resistance.
Step-by-Step Calculation:
1. Calculate the current in Circuit A:
- Resistance ([tex]\( R_A \)[/tex]) = 20 Ω
- Voltage ([tex]\( V_A \)[/tex]) = 24 V
Using Ohm's Law:
[tex]\[ I_A = \frac{V_A}{R_A} = \frac{24 \text{ V}}{20 \text{ Ω}} = 1.2 \text{ A} \][/tex]
2. Calculate the current in Circuit B:
- Resistance ([tex]\( R_B \)[/tex]) = 250 Ω
- Voltage ([tex]\( V_B \)[/tex]) = 220 V
Using Ohm's Law:
[tex]\[ I_B = \frac{V_B}{R_B} = \frac{220 \text{ V}}{250 \text{ Ω}} = 0.88 \text{ A} \][/tex]
3. Calculate the current in Circuit C:
- Resistance ([tex]\( R_C \)[/tex]) = 3 Ω
- Voltage ([tex]\( V_C \)[/tex]) = 6 V
Using Ohm's Law:
[tex]\[ I_C = \frac{V_C}{R_C} = \frac{6 \text{ V}}{3 \text{ Ω}} = 2.0 \text{ A} \][/tex]
Now, we have the currents for each circuit:
- Circuit A: 1.2 A
- Circuit B: 0.88 A
- Circuit C: 2.0 A
Order of currents from highest to lowest:
- Circuit C: 2.0 A
- Circuit A: 1.2 A
- Circuit B: 0.88 A
Therefore, the order that shows decreasing current is:
[tex]\[ \boxed{\text{C, A, B}} \][/tex]
[tex]\[ I = \frac{V}{R} \][/tex]
where [tex]\( I \)[/tex] is the current, [tex]\( V \)[/tex] is the voltage, and [tex]\( R \)[/tex] is the resistance.
Step-by-Step Calculation:
1. Calculate the current in Circuit A:
- Resistance ([tex]\( R_A \)[/tex]) = 20 Ω
- Voltage ([tex]\( V_A \)[/tex]) = 24 V
Using Ohm's Law:
[tex]\[ I_A = \frac{V_A}{R_A} = \frac{24 \text{ V}}{20 \text{ Ω}} = 1.2 \text{ A} \][/tex]
2. Calculate the current in Circuit B:
- Resistance ([tex]\( R_B \)[/tex]) = 250 Ω
- Voltage ([tex]\( V_B \)[/tex]) = 220 V
Using Ohm's Law:
[tex]\[ I_B = \frac{V_B}{R_B} = \frac{220 \text{ V}}{250 \text{ Ω}} = 0.88 \text{ A} \][/tex]
3. Calculate the current in Circuit C:
- Resistance ([tex]\( R_C \)[/tex]) = 3 Ω
- Voltage ([tex]\( V_C \)[/tex]) = 6 V
Using Ohm's Law:
[tex]\[ I_C = \frac{V_C}{R_C} = \frac{6 \text{ V}}{3 \text{ Ω}} = 2.0 \text{ A} \][/tex]
Now, we have the currents for each circuit:
- Circuit A: 1.2 A
- Circuit B: 0.88 A
- Circuit C: 2.0 A
Order of currents from highest to lowest:
- Circuit C: 2.0 A
- Circuit A: 1.2 A
- Circuit B: 0.88 A
Therefore, the order that shows decreasing current is:
[tex]\[ \boxed{\text{C, A, B}} \][/tex]
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