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Sagot :
Let's solve each part of the question step-by-step.
### (a) What is the probability that a randomly selected home run was hit to right field?
To find the probability, we use the formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
In this case:
- The number of favorable outcomes (home runs hit to right field) is 16.
- The total number of outcomes (total home runs) is 55.
So, the probability that a randomly selected home run was hit to right field is:
[tex]\[ \text{Probability} = \frac{16}{55} \approx 0.2909 \][/tex]
Therefore, the probability is approximately 0.2909.
### (b) What is the probability that a randomly selected home run was hit to left field?
Using the same probability formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
In this case:
- The number of favorable outcomes (home runs hit to left field) is 1.
- The total number of outcomes (total home runs) is 55.
So, the probability that a randomly selected home run was hit to left field is:
[tex]\[ \text{Probability} = \frac{1}{55} \approx 0.0182 \][/tex]
Therefore, the probability is approximately 0.0182.
### (c) Was it unusual for this player to hit a home run to left field? Explain.
To determine if an event is unusual, we generally consider whether the probability of the event occurring is less than 0.05 (or 5%).
From part (b), we calculated the probability of hitting a home run to left field to be approximately 0.0182.
Since 0.0182 is less than 0.05, it is considered unusual for this player to hit a home run to left field.
Therefore, it was indeed unusual for this player to hit a home run to left field because the probability of such an event is very low (less than 0.05).
In summary:
(a) The probability that a home run was hit to right field is approximately 0.2909.
(b) The probability that a home run was hit to left field is approximately 0.0182.
(c) It was unusual for the player to hit a home run to left field, as the probability of this happening is less than 0.05.
### (a) What is the probability that a randomly selected home run was hit to right field?
To find the probability, we use the formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
In this case:
- The number of favorable outcomes (home runs hit to right field) is 16.
- The total number of outcomes (total home runs) is 55.
So, the probability that a randomly selected home run was hit to right field is:
[tex]\[ \text{Probability} = \frac{16}{55} \approx 0.2909 \][/tex]
Therefore, the probability is approximately 0.2909.
### (b) What is the probability that a randomly selected home run was hit to left field?
Using the same probability formula:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \][/tex]
In this case:
- The number of favorable outcomes (home runs hit to left field) is 1.
- The total number of outcomes (total home runs) is 55.
So, the probability that a randomly selected home run was hit to left field is:
[tex]\[ \text{Probability} = \frac{1}{55} \approx 0.0182 \][/tex]
Therefore, the probability is approximately 0.0182.
### (c) Was it unusual for this player to hit a home run to left field? Explain.
To determine if an event is unusual, we generally consider whether the probability of the event occurring is less than 0.05 (or 5%).
From part (b), we calculated the probability of hitting a home run to left field to be approximately 0.0182.
Since 0.0182 is less than 0.05, it is considered unusual for this player to hit a home run to left field.
Therefore, it was indeed unusual for this player to hit a home run to left field because the probability of such an event is very low (less than 0.05).
In summary:
(a) The probability that a home run was hit to right field is approximately 0.2909.
(b) The probability that a home run was hit to left field is approximately 0.0182.
(c) It was unusual for the player to hit a home run to left field, as the probability of this happening is less than 0.05.
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