Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Select the correct answer.

A company that packages cold cuts needs to transport the packaged meat to the supermarket. It will cost [tex]$\$[/tex]1,200[tex]$ to rent a truck, and it will cost an additional $[/tex]\[tex]$100$[/tex] for every 50 pounds transported. Which equation represents the transport cost for every 50 pounds of cold cuts transported?

A. [tex]y = 1,200 - 100x[/tex]
B. [tex]y = 1,200 + 100x[/tex]
C. [tex]y = 1,200x + 100[/tex]
D. [tex]y = 100x - 1,200[/tex]


Sagot :

To determine which equation correctly represents the transport cost for every 50 pounds of cold cuts transported, we need to analyze the given cost structure:

1. Fixed Cost: It costs [tex]$1,200 to rent the truck. This fixed cost does not change regardless of the weight transported. 2. Variable Cost: It costs an additional $[/tex]100 for every 50 pounds transported. This cost changes based on the weight being transported.

Let's define the variables:
- Let [tex]\( x \)[/tex] represent the number of units of 50 pounds transported.
- Let [tex]\( y \)[/tex] represent the total transport cost.

Given these definitions:
- The fixed cost [tex]\( \$1,200 \)[/tex] is constant.
- The variable cost is [tex]\( \$100 \)[/tex] per unit of 50 pounds, so the number of units [tex]\( x \)[/tex] will determine this additional cost component.

To generate the total cost [tex]\( y \)[/tex], we combine the fixed cost and the variable cost:
[tex]\[ y = 1200 + (100 \times x) \][/tex]

Therefore, the correct equation that represents the transport cost [tex]\( y \)[/tex] for every [tex]\( x \)[/tex] units of 50 pounds of cold cuts transported is:
[tex]\[ y = 1200 + 100x \][/tex]

Upon evaluating the given multiple-choice options:

A. [tex]\( y = 1200 - 100x \)[/tex] — This option incorrectly subtracts the variable cost, which is not correct.

B. [tex]\( y = 1200 + 100x \)[/tex] — This option correctly adds the variable cost to the fixed cost, aligning with our equation.

C. [tex]\( y = 1200x + 100 \)[/tex] — This option inaccurately multiplies the fixed cost by [tex]\( x \)[/tex] and adds a constant, which is incorrect.

D. [tex]\( y = 100x - 1200 \)[/tex] — This option incorrectly subtracts the fixed cost, which is not correct.

The correct answer is:
[tex]\[ \boxed{B} \][/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.