Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

6. Carbon disulfide combusts in oxygen according to the following unbalanced reaction:

[tex]\[
CS_2(g) + O_2(g) \rightarrow CO_2(g) + SO_2(g)
\][/tex]

If [tex]\(3 \, \text{dm}^3\)[/tex] of [tex]\(CS_2\)[/tex] reacts completely, calculate the:

6.1 Volume of [tex]\(O_2\)[/tex] used.

6.2 Volume of [tex]\(CO_2\)[/tex] and [tex]\(SO_2\)[/tex] produced.

Sagot :

GinnyAnswer
Let's solve the given problem step by step.

The balanced chemical equation for the combustion of carbon disulfide ([tex]\(CS_2\)[/tex]) in oxygen ([tex]\(O_2\)[/tex]) is as follows:

[tex]\[ CS_2(g) + 3O_2(g) \rightarrow CO_2(g) + 2SO_2(g) \][/tex]

We need to calculate the volumes of [tex]\(O_2\)[/tex], [tex]\(CO_2\)[/tex], and [tex]\(SO_2\)[/tex] involved in the reaction when [tex]\(3 \, \text{dm}^3\)[/tex] of [tex]\(CS_2\)[/tex] reacts completely.

### Part 6.1: Volume of [tex]\(O_2\)[/tex] used

From the balanced equation, we see that 1 volume of [tex]\(CS_2\)[/tex] reacts with 3 volumes of [tex]\(O_2\)[/tex]. Therefore, the volume of [tex]\(O_2\)[/tex] used will be three times the volume of [tex]\(CS_2\)[/tex].

Given:
- Volume of [tex]\(CS_2 = 3 \, \text{dm}^3\)[/tex]

Using the stoichiometric ratio from the balanced equation:
- Volume of [tex]\(O_2\)[/tex] used = Volume of [tex]\(CS_2\)[/tex] [tex]\(\times 3\)[/tex]
- Volume of [tex]\(O_2\)[/tex] used = [tex]\(3 \, \text{dm}^3 \times 3 = 9 \, \text{dm}^3\)[/tex]

### Part 6.2: Volume of [tex]\(CO_2\)[/tex] and [tex]\(SO_2\)[/tex] made

From the balanced equation, we also see that:
- 1 volume of [tex]\(CS_2\)[/tex] produces 1 volume of [tex]\(CO_2\)[/tex].
- 1 volume of [tex]\(CS_2\)[/tex] produces 2 volumes of [tex]\(SO_2\)[/tex].

Therefore,
- Volume of [tex]\(CO_2\)[/tex] produced = Volume of [tex]\(CS_2 \, (\text{dm}^3}) = 3 \, \text{dm}^3 - Volume of \(SO_2\)[/tex] produced = Volume of [tex]\(CS_2\)[/tex] [tex]\(\times 2\)[/tex] = [tex]\(3 \, \text{dm}^3 \times 2 = 6 \, \text{dm}^3\)[/tex]

### Summary

When [tex]\(3 \, \text{dm}^3\)[/tex] of [tex]\(CS_2\)[/tex] reacts completely:
- Volume of [tex]\(O_2\)[/tex] used is [tex]\(9 \, \text{dm}^3\)[/tex].
- Volume of [tex]\(CO_2\)[/tex] produced is [tex]\(3 \, \text{dm}^3\)[/tex].
- Volume of [tex]\(SO_2\)[/tex] produced is [tex]\(6 \, \text{dm}^3\)[/tex].

Thus, the answers are:
1. Volume of [tex]\(O_2\)[/tex] used: [tex]\(9 \, \text{dm}^3\)[/tex]
2. Volume of [tex]\(CO_2\)[/tex] produced: [tex]\(3 \, \text{dm}^3\)[/tex]
3. Volume of [tex]\(SO_2\)[/tex] produced: [tex]\(6 \, \text{dm}^3\)[/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.