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Sagot :
Sure, let's solve the problem step-by-step.
### Part (a): Find the Hypotenuse
To find the hypotenuse in a right triangle when the lengths of the two legs are given, we use the Pythagorean theorem. The theorem is stated as follows:
[tex]\[ c^2 = a^2 + b^2 \][/tex]
where [tex]\(c\)[/tex] is the hypotenuse, and [tex]\(a\)[/tex] and [tex]\(b\)[/tex] are the legs of the triangle.
Given:
[tex]\[ a = 5.00 \][/tex]
[tex]\[ b = 8.00 \][/tex]
Substitute these values into the Pythagorean theorem:
[tex]\[ c^2 = 5.00^2 + 8.00^2 \][/tex]
Calculate the squares:
[tex]\[ c^2 = 25.00 + 64.00 \][/tex]
[tex]\[ c^2 = 89.00 \][/tex]
Now, take the square root of both sides to find [tex]\(c\)[/tex]:
[tex]\[ c = \sqrt{89.00} \approx 9.43 \][/tex]
So the hypotenuse is approximately [tex]\(9.43\)[/tex] (rounded to two decimal places).
### Part (b): Find the Two Acute Angles
To find the acute angles in a right triangle, we can use trigonometric functions. Specifically, we use the arctangent (inverse tangent) function, which relates the ratio of the legs to the angles.
Let [tex]\(\theta_1\)[/tex] and [tex]\(\theta_2\)[/tex] be the two acute angles.
1. Calculate [tex]\(\theta_1\)[/tex]:
[tex]\[ \theta_1 = \arctan\left(\frac{a}{b}\right) \][/tex]
[tex]\[ \theta_1 = \arctan\left(\frac{5.00}{8.00}\right) \][/tex]
Using a calculator to find the arctan and then converting it to degrees:
[tex]\[ \theta_1 \approx 32.0^\circ \][/tex]
2. Calculate [tex]\(\theta_2\)[/tex]:
[tex]\[ \theta_2 = \arctan\left(\frac{b}{a}\right) \][/tex]
[tex]\[ \theta_2 = \arctan\left(\frac{8.00}{5.00}\right) \][/tex]
Using a calculator to find the arctan and then converting it to degrees:
[tex]\[ \theta_2 \approx 58.0^\circ \][/tex]
Thus, the two acute angles are approximately [tex]\(32.0^\circ\)[/tex] and [tex]\(58.0^\circ\)[/tex] (rounded to one decimal place).
### Final Answer:
a) The hypotenuse is [tex]\(9.43\)[/tex].
b) The two acute angles are [tex]\(32.0^\circ\)[/tex] and [tex]\(58.0^\circ\)[/tex].
### Part (a): Find the Hypotenuse
To find the hypotenuse in a right triangle when the lengths of the two legs are given, we use the Pythagorean theorem. The theorem is stated as follows:
[tex]\[ c^2 = a^2 + b^2 \][/tex]
where [tex]\(c\)[/tex] is the hypotenuse, and [tex]\(a\)[/tex] and [tex]\(b\)[/tex] are the legs of the triangle.
Given:
[tex]\[ a = 5.00 \][/tex]
[tex]\[ b = 8.00 \][/tex]
Substitute these values into the Pythagorean theorem:
[tex]\[ c^2 = 5.00^2 + 8.00^2 \][/tex]
Calculate the squares:
[tex]\[ c^2 = 25.00 + 64.00 \][/tex]
[tex]\[ c^2 = 89.00 \][/tex]
Now, take the square root of both sides to find [tex]\(c\)[/tex]:
[tex]\[ c = \sqrt{89.00} \approx 9.43 \][/tex]
So the hypotenuse is approximately [tex]\(9.43\)[/tex] (rounded to two decimal places).
### Part (b): Find the Two Acute Angles
To find the acute angles in a right triangle, we can use trigonometric functions. Specifically, we use the arctangent (inverse tangent) function, which relates the ratio of the legs to the angles.
Let [tex]\(\theta_1\)[/tex] and [tex]\(\theta_2\)[/tex] be the two acute angles.
1. Calculate [tex]\(\theta_1\)[/tex]:
[tex]\[ \theta_1 = \arctan\left(\frac{a}{b}\right) \][/tex]
[tex]\[ \theta_1 = \arctan\left(\frac{5.00}{8.00}\right) \][/tex]
Using a calculator to find the arctan and then converting it to degrees:
[tex]\[ \theta_1 \approx 32.0^\circ \][/tex]
2. Calculate [tex]\(\theta_2\)[/tex]:
[tex]\[ \theta_2 = \arctan\left(\frac{b}{a}\right) \][/tex]
[tex]\[ \theta_2 = \arctan\left(\frac{8.00}{5.00}\right) \][/tex]
Using a calculator to find the arctan and then converting it to degrees:
[tex]\[ \theta_2 \approx 58.0^\circ \][/tex]
Thus, the two acute angles are approximately [tex]\(32.0^\circ\)[/tex] and [tex]\(58.0^\circ\)[/tex] (rounded to one decimal place).
### Final Answer:
a) The hypotenuse is [tex]\(9.43\)[/tex].
b) The two acute angles are [tex]\(32.0^\circ\)[/tex] and [tex]\(58.0^\circ\)[/tex].
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