Answered

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[tex]$a \cdot 117+67+318+413$[/tex]

c. [tex]$91+84+59+3936$[/tex]

e. [tex]$217+318+143+412$[/tex]

Multiply using the property:

a. [tex]$102 \times 64$[/tex]

b. [tex]$13 \times 10$[/tex]

Sagot :

GinnyAnswer
Certainly! Let's break down the problem step-by-step, as if we were solving it manually, to reach the results.

### Part (a):
Calculate the sum of the given numbers:
[tex]\[ 117 + 67 + 318 + 413 \][/tex]

Adding these step-by-step:
1. [tex]\( 117 + 67 = 184 \)[/tex]
2. [tex]\( 184 + 318 = 502 \)[/tex]
3. [tex]\( 502 + 413 = 915 \)[/tex]

So, the result of part (a) is:
[tex]\[ 915 \][/tex]

### Part (c):
Calculate the sum of the given numbers:
[tex]\[ 91 + 84 + 59 + 3936 \][/tex]

Adding these step-by-step:
1. [tex]\( 91 + 84 = 175 \)[/tex]
2. [tex]\( 175 + 59 = 234 \)[/tex]
3. [tex]\( 234 + 3936 = 4170 \)[/tex]

So, the result of part (c) is:
[tex]\[ 4170 \][/tex]

### Part (e):
Calculate the sum of the given numbers:
[tex]\[ 217 + 318 + 143 + 412 \][/tex]

Adding these step-by-step:
1. [tex]\( 217 + 318 = 535 \)[/tex]
2. [tex]\( 535 + 143 = 678 \)[/tex]
3. [tex]\( 678 + 412 = 1090 \)[/tex]

So, the result of part (e) is:
[tex]\[ 1090 \][/tex]

### Part (b):
Calculate the product of the given numbers:
[tex]\[ 13 \times 10 \][/tex]

Multiplying directly:
[tex]\[ 13 \times 10 = 130 \][/tex]

So, the result of part (b) is:
[tex]\[ 130 \][/tex]

### Part (f):
Calculate the product of the given numbers:
[tex]\[ 102 \times 64 \][/tex]

Multiplying directly:
[tex]\[ 102 \times 64 = 6528 \][/tex]

So, the result of part (f) is:
[tex]\[ 6528 \][/tex]

To summarize, here are the results for each part:
- (a) [tex]\( 117 + 67 + 318 + 413 = 915 \)[/tex]
- (c) [tex]\( 91 + 84 + 59 + 3936 = 4170 \)[/tex]
- (e) [tex]\( 217 + 318 + 143 + 412 = 1090 \)[/tex]
- (b) [tex]\( 13 \times 10 = 130 \)[/tex]
- (f) [tex]\( 102 \times 64 = 6528 \)[/tex]
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