Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Sure, let's walk through the problem step by step:
1. Identify the Genotypes of the Parents:
- One parent is homozygous recessive for both traits: [tex]\( bbee \)[/tex].
- The other parent is a dihybrid: [tex]\( BbEe \)[/tex].
2. Determine the Possible Gametes for Each Parent:
- The homozygous recessive parent (bbee) can only produce one type of gamete: [tex]\( be \)[/tex].
- The dihybrid parent (BbEe) can produce four types of gametes through meiosis: [tex]\( BE \)[/tex], [tex]\( Be \)[/tex], [tex]\( bE \)[/tex], and [tex]\( be \)[/tex].
3. Set Up the Punnett Square:
- The top row (or column) of the Punnett square will be the gametes from the homozygous recessive parent: [tex]\( be \)[/tex].
- The side row (or column) will be the gametes from the dihybrid parent: [tex]\( BE \)[/tex], [tex]\( Be \)[/tex], [tex]\( bE \)[/tex], [tex]\( be \)[/tex].
Constructing the Punnett square:
```
be
-----------------
BE | BbEe
Be | Bbee
bE | bbEe
be | bbee
```
4. Determine the Genotype of Each Offspring:
- Combining the gametes, we have these possible outcomes:
- [tex]\( BE \times be = BbEe \)[/tex]
- [tex]\( Be \times be = Bbee \)[/tex]
- [tex]\( bE \times be = bbEe \)[/tex]
- [tex]\( be \times be = bbee \)[/tex]
5. Determine the Phenotype of Each Offspring:
- For [tex]\( BbEe \)[/tex]: Black Fur and Black Eyes (1 combination)
- For [tex]\( Bbee \)[/tex]: Black Fur and Black Eyes (1 combination)
- For [tex]\( bbEe \)[/tex]: White Fur and Black Eyes (1 combination)
- For [tex]\( bbee \)[/tex]: White Fur and Red Eyes (1 combination)
Since the homozygous recessive parent always pairs with the same gamete type, each combination will occur 4 times in our resulting 16-box Punnett square.
6. Determine the Phenotype Ratios for the Offspring:
- Black Fur and Black Eyes (BbEe and Bbee): Occurs 4 times out of 16
- Black Fur and Red Eyes: Does not occur
- White Fur and Black Eyes (bbEe): Occurs 2 times out of 16
- White Fur and Red Eyes (bbee): Occurs 2 times out of 16
7. Fill in the Predicted Fraction of Each Phenotype:
```
\begin{tabular}{|l||c|c|c|c|}
\hline & \begin{tabular}{c}
Black \\
Fur and \\
Black \\
Eyes
\end{tabular} & \begin{tabular}{c}
Black \\
Fur and \\
Red \\
Eyes
\end{tabular} & \begin{tabular}{c}
White \\
Fur and \\
Black \\
Eyes
\end{tabular} & \begin{tabular}{c}
White \\
Fur and \\
Red \\
Eyes
\end{tabular} \\
\hline \begin{tabular}{l}
Predicted \\
Fraction
\end{tabular} & 4 / 16 & 0 / 16 & 2 / 16 & 2 / 16 \\
\hline
\end{tabular}
```
1. Identify the Genotypes of the Parents:
- One parent is homozygous recessive for both traits: [tex]\( bbee \)[/tex].
- The other parent is a dihybrid: [tex]\( BbEe \)[/tex].
2. Determine the Possible Gametes for Each Parent:
- The homozygous recessive parent (bbee) can only produce one type of gamete: [tex]\( be \)[/tex].
- The dihybrid parent (BbEe) can produce four types of gametes through meiosis: [tex]\( BE \)[/tex], [tex]\( Be \)[/tex], [tex]\( bE \)[/tex], and [tex]\( be \)[/tex].
3. Set Up the Punnett Square:
- The top row (or column) of the Punnett square will be the gametes from the homozygous recessive parent: [tex]\( be \)[/tex].
- The side row (or column) will be the gametes from the dihybrid parent: [tex]\( BE \)[/tex], [tex]\( Be \)[/tex], [tex]\( bE \)[/tex], [tex]\( be \)[/tex].
Constructing the Punnett square:
```
be
-----------------
BE | BbEe
Be | Bbee
bE | bbEe
be | bbee
```
4. Determine the Genotype of Each Offspring:
- Combining the gametes, we have these possible outcomes:
- [tex]\( BE \times be = BbEe \)[/tex]
- [tex]\( Be \times be = Bbee \)[/tex]
- [tex]\( bE \times be = bbEe \)[/tex]
- [tex]\( be \times be = bbee \)[/tex]
5. Determine the Phenotype of Each Offspring:
- For [tex]\( BbEe \)[/tex]: Black Fur and Black Eyes (1 combination)
- For [tex]\( Bbee \)[/tex]: Black Fur and Black Eyes (1 combination)
- For [tex]\( bbEe \)[/tex]: White Fur and Black Eyes (1 combination)
- For [tex]\( bbee \)[/tex]: White Fur and Red Eyes (1 combination)
Since the homozygous recessive parent always pairs with the same gamete type, each combination will occur 4 times in our resulting 16-box Punnett square.
6. Determine the Phenotype Ratios for the Offspring:
- Black Fur and Black Eyes (BbEe and Bbee): Occurs 4 times out of 16
- Black Fur and Red Eyes: Does not occur
- White Fur and Black Eyes (bbEe): Occurs 2 times out of 16
- White Fur and Red Eyes (bbee): Occurs 2 times out of 16
7. Fill in the Predicted Fraction of Each Phenotype:
```
\begin{tabular}{|l||c|c|c|c|}
\hline & \begin{tabular}{c}
Black \\
Fur and \\
Black \\
Eyes
\end{tabular} & \begin{tabular}{c}
Black \\
Fur and \\
Red \\
Eyes
\end{tabular} & \begin{tabular}{c}
White \\
Fur and \\
Black \\
Eyes
\end{tabular} & \begin{tabular}{c}
White \\
Fur and \\
Red \\
Eyes
\end{tabular} \\
\hline \begin{tabular}{l}
Predicted \\
Fraction
\end{tabular} & 4 / 16 & 0 / 16 & 2 / 16 & 2 / 16 \\
\hline
\end{tabular}
```
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
