Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Let's start by breaking down each part of the composite functions as well as determining the domains.
### Composite Functions:
#### (a) [tex]\( f \circ g \)[/tex]
The notation [tex]\( f \circ g \)[/tex] means [tex]\( f(g(x)) \)[/tex].
Given [tex]\( g(x) = x + 1 \)[/tex], we need to evaluate [tex]\( f \)[/tex] at [tex]\( g(x) \)[/tex]:
[tex]\[ f(g(x)) = f(x + 1) \][/tex]
Since [tex]\( f(x) = |x| \)[/tex], we substitute [tex]\( x + 1 \)[/tex] into [tex]\( f \)[/tex]:
[tex]\[ f(x + 1) = |x + 1| \][/tex]
Thus:
[tex]\[ f \circ g (x) = |x + 1| \][/tex]
#### (b) [tex]\( g \circ f \)[/tex]
The notation [tex]\( g \circ f \)[/tex] means [tex]\( g(f(x)) \)[/tex].
Given [tex]\( f(x) = |x| \)[/tex], we need to evaluate [tex]\( g \)[/tex] at [tex]\( f(x) \)[/tex]:
[tex]\[ g(f(x)) = g(|x|) \][/tex]
Since [tex]\( g(x) = x + 1 \)[/tex], we substitute [tex]\( |x| \)[/tex] into [tex]\( g \)[/tex]:
[tex]\[ g(|x|) = |x| + 1 \][/tex]
Thus:
[tex]\[ g \circ f (x) = |x| + 1 \][/tex]
### Evaluating Composite Functions at a Given Point:
Evaluating these composite functions at [tex]\( x = 2 \)[/tex]:
- For [tex]\( f \circ g (2) \)[/tex]:
[tex]\[ f(g(2)) = f(2 + 1) = f(3) = |3| = 3 \][/tex]
- For [tex]\( g \circ f (2) \)[/tex]:
[tex]\[ g(f(2)) = g(|2|) = g(2) = 2 + 1 = 3 \][/tex]
So, the evaluations are:
[tex]\[ f \circ g (2) = 3 \][/tex]
[tex]\[ g \circ f (2) = 3 \][/tex]
### Domains:
The domain of a function [tex]\( f \)[/tex] is the set of all [tex]\( x \)[/tex] for which the function is defined.
- Domain of [tex]\( f(x) = |x| \)[/tex]:
- The absolute value function [tex]\( f(x) = |x| \)[/tex] is defined for all real numbers.
- Therefore, the domain of [tex]\( f \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
- Domain of [tex]\( g(x) = x + 1 \)[/tex]:
- The linear function [tex]\( g(x) = x + 1 \)[/tex] is also defined for all real numbers.
- Therefore, the domain of [tex]\( g \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
- Domain of [tex]\( f \circ g (x) = |x + 1| \)[/tex]:
- Since both [tex]\( f \)[/tex] and [tex]\( g \)[/tex] are defined for all real numbers, [tex]\( f(g(x)) \)[/tex] is defined for all real numbers.
- Therefore, the domain of [tex]\( f \circ g \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
- Domain of [tex]\( g \circ f (x) = |x| + 1 \)[/tex]:
- Similarly, since both [tex]\( f \)[/tex] and [tex]\( g \)[/tex] are defined for all real numbers, [tex]\( g(f(x)) \)[/tex] is defined for all real numbers.
- Therefore, the domain of [tex]\( g \circ f \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
### Summary:
- The evaluations of the composite functions at [tex]\( x = 2 \)[/tex] are:
[tex]\[ f \circ g (2) = 3 \][/tex]
[tex]\[ g \circ f (2) = 3 \][/tex]
- Domains:
- Domain of [tex]\( f \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
- Domain of [tex]\( g \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
- Domain of [tex]\( f \circ g \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
- Domain of [tex]\( g \circ f \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
### Composite Functions:
#### (a) [tex]\( f \circ g \)[/tex]
The notation [tex]\( f \circ g \)[/tex] means [tex]\( f(g(x)) \)[/tex].
Given [tex]\( g(x) = x + 1 \)[/tex], we need to evaluate [tex]\( f \)[/tex] at [tex]\( g(x) \)[/tex]:
[tex]\[ f(g(x)) = f(x + 1) \][/tex]
Since [tex]\( f(x) = |x| \)[/tex], we substitute [tex]\( x + 1 \)[/tex] into [tex]\( f \)[/tex]:
[tex]\[ f(x + 1) = |x + 1| \][/tex]
Thus:
[tex]\[ f \circ g (x) = |x + 1| \][/tex]
#### (b) [tex]\( g \circ f \)[/tex]
The notation [tex]\( g \circ f \)[/tex] means [tex]\( g(f(x)) \)[/tex].
Given [tex]\( f(x) = |x| \)[/tex], we need to evaluate [tex]\( g \)[/tex] at [tex]\( f(x) \)[/tex]:
[tex]\[ g(f(x)) = g(|x|) \][/tex]
Since [tex]\( g(x) = x + 1 \)[/tex], we substitute [tex]\( |x| \)[/tex] into [tex]\( g \)[/tex]:
[tex]\[ g(|x|) = |x| + 1 \][/tex]
Thus:
[tex]\[ g \circ f (x) = |x| + 1 \][/tex]
### Evaluating Composite Functions at a Given Point:
Evaluating these composite functions at [tex]\( x = 2 \)[/tex]:
- For [tex]\( f \circ g (2) \)[/tex]:
[tex]\[ f(g(2)) = f(2 + 1) = f(3) = |3| = 3 \][/tex]
- For [tex]\( g \circ f (2) \)[/tex]:
[tex]\[ g(f(2)) = g(|2|) = g(2) = 2 + 1 = 3 \][/tex]
So, the evaluations are:
[tex]\[ f \circ g (2) = 3 \][/tex]
[tex]\[ g \circ f (2) = 3 \][/tex]
### Domains:
The domain of a function [tex]\( f \)[/tex] is the set of all [tex]\( x \)[/tex] for which the function is defined.
- Domain of [tex]\( f(x) = |x| \)[/tex]:
- The absolute value function [tex]\( f(x) = |x| \)[/tex] is defined for all real numbers.
- Therefore, the domain of [tex]\( f \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
- Domain of [tex]\( g(x) = x + 1 \)[/tex]:
- The linear function [tex]\( g(x) = x + 1 \)[/tex] is also defined for all real numbers.
- Therefore, the domain of [tex]\( g \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
- Domain of [tex]\( f \circ g (x) = |x + 1| \)[/tex]:
- Since both [tex]\( f \)[/tex] and [tex]\( g \)[/tex] are defined for all real numbers, [tex]\( f(g(x)) \)[/tex] is defined for all real numbers.
- Therefore, the domain of [tex]\( f \circ g \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
- Domain of [tex]\( g \circ f (x) = |x| + 1 \)[/tex]:
- Similarly, since both [tex]\( f \)[/tex] and [tex]\( g \)[/tex] are defined for all real numbers, [tex]\( g(f(x)) \)[/tex] is defined for all real numbers.
- Therefore, the domain of [tex]\( g \circ f \)[/tex] is [tex]\( (-\infty, \infty) \)[/tex].
### Summary:
- The evaluations of the composite functions at [tex]\( x = 2 \)[/tex] are:
[tex]\[ f \circ g (2) = 3 \][/tex]
[tex]\[ g \circ f (2) = 3 \][/tex]
- Domains:
- Domain of [tex]\( f \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
- Domain of [tex]\( g \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
- Domain of [tex]\( f \circ g \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
- Domain of [tex]\( g \circ f \)[/tex]: [tex]\( (-\infty, \infty) \)[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.