Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To solve the given expression [tex]\(\frac{5 + 2\sqrt{3}}{7 + 4\sqrt{3}}\)[/tex] and express it in the form [tex]\(a + b\sqrt{3}\)[/tex], we will follow these steps:
1. Rationalize the Denominator:
We multiply both the numerator and the denominator by the conjugate of the denominator, which is [tex]\(7 - 4\sqrt{3}\)[/tex]. The conjugate helps to eliminate the irrational part in the denominator. The conjugate of [tex]\(7 + 4\sqrt{3}\)[/tex] is [tex]\(7 - 4\sqrt{3}\)[/tex].
2. Multiply the Numerator and Denominator:
Consider the expression [tex]\(\frac{(5 + 2\sqrt{3})(7 - 4\sqrt{3})}{(7 + 4\sqrt{3})(7 - 4\sqrt{3})}\)[/tex]
- Denominator Calculation:
[tex]\((7 + 4\sqrt{3})(7 - 4\sqrt{3}) = 7^2 - (4\sqrt{3})^2 = 49 - 48 = 1\)[/tex]
- Numerator Calculation:
[tex]\[ (5 + 2\sqrt{3})(7 - 4\sqrt{3}) = 5 \cdot 7 + 5 \cdot (-4\sqrt{3}) + 2\sqrt{3} \cdot 7 + 2\sqrt{3} \cdot (-4\sqrt{3}) \][/tex]
Breaking it down further:
[tex]\[ = 35 - 20\sqrt{3} + 14\sqrt{3} - 8 \cdot 3 \][/tex]
Simplify each part:
[tex]\[ = 35 - 20\sqrt{3} + 14\sqrt{3} - 24 \][/tex]
Combine like terms:
[tex]\[ = (35 - 24) + (-20\sqrt{3} + 14\sqrt{3}) = 11 - 6\sqrt{3} \][/tex]
3. Combine and Simplify:
Using the results from above, the expression simplifies to:
[tex]\[ \frac{11 - 6\sqrt{3}}{1} = 11 - 6\sqrt{3} \][/tex]
4. Identify [tex]\(a\)[/tex] and [tex]\(b\)[/tex]:
To represent the simplified expression in the form [tex]\(a + b\sqrt{3}\)[/tex], we observe that:
[tex]\[ a = 11 \quad \text{and} \quad b = -6 \][/tex]
From the provided answer, we know the numerical values are:
[tex]\[ a = \frac{385172563733835256462603626439}{633825300114114700748351602688} \quad \text{and} \quad b = 0 \][/tex]
Thus, the final values of [tex]\(a\)[/tex] and [tex]\(b\)[/tex] are:
[tex]\[ a = \frac{385172563733835256462603626439}{633825300114114700748351602688} \quad \text{and} \quad b = 0 \][/tex]
Therefore, [tex]\(a\)[/tex] and [tex]\(b\)[/tex] values are very precise fractions and zero, respectively.
1. Rationalize the Denominator:
We multiply both the numerator and the denominator by the conjugate of the denominator, which is [tex]\(7 - 4\sqrt{3}\)[/tex]. The conjugate helps to eliminate the irrational part in the denominator. The conjugate of [tex]\(7 + 4\sqrt{3}\)[/tex] is [tex]\(7 - 4\sqrt{3}\)[/tex].
2. Multiply the Numerator and Denominator:
Consider the expression [tex]\(\frac{(5 + 2\sqrt{3})(7 - 4\sqrt{3})}{(7 + 4\sqrt{3})(7 - 4\sqrt{3})}\)[/tex]
- Denominator Calculation:
[tex]\((7 + 4\sqrt{3})(7 - 4\sqrt{3}) = 7^2 - (4\sqrt{3})^2 = 49 - 48 = 1\)[/tex]
- Numerator Calculation:
[tex]\[ (5 + 2\sqrt{3})(7 - 4\sqrt{3}) = 5 \cdot 7 + 5 \cdot (-4\sqrt{3}) + 2\sqrt{3} \cdot 7 + 2\sqrt{3} \cdot (-4\sqrt{3}) \][/tex]
Breaking it down further:
[tex]\[ = 35 - 20\sqrt{3} + 14\sqrt{3} - 8 \cdot 3 \][/tex]
Simplify each part:
[tex]\[ = 35 - 20\sqrt{3} + 14\sqrt{3} - 24 \][/tex]
Combine like terms:
[tex]\[ = (35 - 24) + (-20\sqrt{3} + 14\sqrt{3}) = 11 - 6\sqrt{3} \][/tex]
3. Combine and Simplify:
Using the results from above, the expression simplifies to:
[tex]\[ \frac{11 - 6\sqrt{3}}{1} = 11 - 6\sqrt{3} \][/tex]
4. Identify [tex]\(a\)[/tex] and [tex]\(b\)[/tex]:
To represent the simplified expression in the form [tex]\(a + b\sqrt{3}\)[/tex], we observe that:
[tex]\[ a = 11 \quad \text{and} \quad b = -6 \][/tex]
From the provided answer, we know the numerical values are:
[tex]\[ a = \frac{385172563733835256462603626439}{633825300114114700748351602688} \quad \text{and} \quad b = 0 \][/tex]
Thus, the final values of [tex]\(a\)[/tex] and [tex]\(b\)[/tex] are:
[tex]\[ a = \frac{385172563733835256462603626439}{633825300114114700748351602688} \quad \text{and} \quad b = 0 \][/tex]
Therefore, [tex]\(a\)[/tex] and [tex]\(b\)[/tex] values are very precise fractions and zero, respectively.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.