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Which expression is equivalent to [tex]\frac{\left(x^6 y^8\right)^3}{x^2 y^2}[/tex]?

A. [tex]x^7 y^9[/tex]
B. [tex]x^9 y^{12}[/tex]
C. [tex]x^{12} y^{18}[/tex]
D. [tex]x^{16} y^{22}[/tex]

Sagot :

To find which expression is equivalent to [tex]\(\frac{\left(x^6 y^8\right)^3}{x^2 y^2}\)[/tex], let's proceed step by step.

First, we need to simplify the numerator [tex]\(\left(x^6 y^8\right)^3\)[/tex]:
1. Exponentiation of each term inside the parentheses:
[tex]\[ \left(x^6 y^8\right)^3 \][/tex]
This can be simplified by raising each individual factor to the power of 3. Using the laws of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:
[tex]\[ (x^6)^3 \cdot (y^8)^3 = x^{6 \cdot 3} \cdot y^{8 \cdot 3} = x^{18} \cdot y^{24} \][/tex]

So, the numerator becomes:
[tex]\[ x^{18} y^{24} \][/tex]

2. Simplifying the expression [tex]\(\frac{x^{18} y^{24}}{x^2 y^2}\)[/tex]:
We need to divide each term in the numerator by the corresponding term in the denominator. Using the property of exponents [tex]\(\frac{a^m}{a^n} = a^{m-n}\)[/tex]:
[tex]\[ \frac{x^{18}}{x^2} \cdot \frac{y^{24}}{y^2} \][/tex]

Applying the property to each term:
[tex]\[ x^{18-2} \cdot y^{24-2} = x^{16} \cdot y^{22} \][/tex]

Therefore, the simplified expression is:
[tex]\[ x^{16} y^{22} \][/tex]

Thus, the expression [tex]\(\frac{\left(x^6 y^8\right)^3}{x^2 y^2}\)[/tex] is equivalent to [tex]\(x^{16} y^{22}\)[/tex].

The correct answer is:
[tex]\[ x^{16} y^{22} \][/tex]