Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Which expression is equivalent to [tex]\frac{\left(x^6 y^8\right)^3}{x^2 y^2}[/tex]?

A. [tex]x^7 y^9[/tex]
B. [tex]x^9 y^{12}[/tex]
C. [tex]x^{12} y^{18}[/tex]
D. [tex]x^{16} y^{22}[/tex]


Sagot :

To find which expression is equivalent to [tex]\(\frac{\left(x^6 y^8\right)^3}{x^2 y^2}\)[/tex], let's proceed step by step.

First, we need to simplify the numerator [tex]\(\left(x^6 y^8\right)^3\)[/tex]:
1. Exponentiation of each term inside the parentheses:
[tex]\[ \left(x^6 y^8\right)^3 \][/tex]
This can be simplified by raising each individual factor to the power of 3. Using the laws of exponents [tex]\((a^m)^n = a^{m \cdot n}\)[/tex]:
[tex]\[ (x^6)^3 \cdot (y^8)^3 = x^{6 \cdot 3} \cdot y^{8 \cdot 3} = x^{18} \cdot y^{24} \][/tex]

So, the numerator becomes:
[tex]\[ x^{18} y^{24} \][/tex]

2. Simplifying the expression [tex]\(\frac{x^{18} y^{24}}{x^2 y^2}\)[/tex]:
We need to divide each term in the numerator by the corresponding term in the denominator. Using the property of exponents [tex]\(\frac{a^m}{a^n} = a^{m-n}\)[/tex]:
[tex]\[ \frac{x^{18}}{x^2} \cdot \frac{y^{24}}{y^2} \][/tex]

Applying the property to each term:
[tex]\[ x^{18-2} \cdot y^{24-2} = x^{16} \cdot y^{22} \][/tex]

Therefore, the simplified expression is:
[tex]\[ x^{16} y^{22} \][/tex]

Thus, the expression [tex]\(\frac{\left(x^6 y^8\right)^3}{x^2 y^2}\)[/tex] is equivalent to [tex]\(x^{16} y^{22}\)[/tex].

The correct answer is:
[tex]\[ x^{16} y^{22} \][/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.