Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Sure, let's factor the polynomial [tex]\(4x^5 - 20x^4 - 36x^3\)[/tex] step by step completely.
1. Identify the greatest common factor (GCF):
Look at the coefficients: [tex]\(4, -20, -36\)[/tex]. The greatest common factor of these numbers is 4.
Also note that each term contains at least [tex]\(x^3\)[/tex]. So, the GCF of all the terms is [tex]\(4x^3\)[/tex].
Factor out the GCF:
[tex]\[ 4x^5 - 20x^4 - 36x^3 = 4x^3 (x^2 - 5x - 9) \][/tex]
2. Factor the remaining polynomial [tex]\(x^2 - 5x - 9): Check if it can be factored further. We look for two numbers that multiply to \(-9\)[/tex] (the constant term) and add up to [tex]\(-5\)[/tex] (the coefficient of the linear term).
In this case, there are no integer factors of [tex]\(-9\)[/tex] that sum to [tex]\(-5\)[/tex]. Hence, the quadratic polynomial [tex]\(x^2 - 5x - 9\)[/tex] cannot be factored over the integers.
Thus, the polynomial completely factored is:
[tex]\[ 4x^3 (x^2 - 5x - 9) \][/tex]
This is the fully factored form of the polynomial [tex]\(4x^5 - 20x^4 - 36x^3\)[/tex].
Final Answer:
[tex]\[ 4x^3(x^2 - 5x - 9) \][/tex]
1. Identify the greatest common factor (GCF):
Look at the coefficients: [tex]\(4, -20, -36\)[/tex]. The greatest common factor of these numbers is 4.
Also note that each term contains at least [tex]\(x^3\)[/tex]. So, the GCF of all the terms is [tex]\(4x^3\)[/tex].
Factor out the GCF:
[tex]\[ 4x^5 - 20x^4 - 36x^3 = 4x^3 (x^2 - 5x - 9) \][/tex]
2. Factor the remaining polynomial [tex]\(x^2 - 5x - 9): Check if it can be factored further. We look for two numbers that multiply to \(-9\)[/tex] (the constant term) and add up to [tex]\(-5\)[/tex] (the coefficient of the linear term).
In this case, there are no integer factors of [tex]\(-9\)[/tex] that sum to [tex]\(-5\)[/tex]. Hence, the quadratic polynomial [tex]\(x^2 - 5x - 9\)[/tex] cannot be factored over the integers.
Thus, the polynomial completely factored is:
[tex]\[ 4x^3 (x^2 - 5x - 9) \][/tex]
This is the fully factored form of the polynomial [tex]\(4x^5 - 20x^4 - 36x^3\)[/tex].
Final Answer:
[tex]\[ 4x^3(x^2 - 5x - 9) \][/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.