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Evaluate the integral.
[tex]\[ \int_1^e \left(16x - \frac{5}{x}\right) dx \][/tex]
(Express your answer in terms of [tex]\( e \)[/tex].)

A. [tex]\( 8e^2 - 13 \)[/tex]
B. [tex]\( 8e^2 - 8 \)[/tex]
C. [tex]\( 16e^2 - 5 \)[/tex]
D. [tex]\( 8e^2 - 5 \)[/tex]

Sagot :

To evaluate the integral [tex]\(\int_1^e \left(16x - \frac{5}{x}\right) \, dx\)[/tex], follow these steps:

1. Separate the integral into two parts:
[tex]\[ \int_1^e \left(16x - \frac{5}{x}\right) \, dx = \int_1^e 16x \, dx - \int_1^e \frac{5}{x} \, dx \][/tex]

2. Compute each integral individually:

- For the first integral [tex]\(\int_1^e 16x \, dx\)[/tex]:
[tex]\[ \int 16x \, dx = 16 \int x \, dx = 16 \left(\frac{x^2}{2}\right) = 8x^2 \][/tex]
Evaluate this result from 1 to [tex]\(e\)[/tex]:
[tex]\[ \left. 8x^2 \right|_1^e = 8e^2 - 8 \][/tex]

- For the second integral [tex]\(\int_1^e \frac{5}{x} \, dx\)[/tex]:
[tex]\[ \int \frac{5}{x} \, dx = 5 \int \frac{1}{x} \, dx = 5 \ln|x| \][/tex]
Evaluate this result from 1 to [tex]\(e\)[/tex]:
[tex]\[ \left. 5 \ln|x| \right|_1^e = 5 \ln e - 5 \ln 1 = 5 \cdot 1 - 5 \cdot 0 = 5 \][/tex]

3. Combine the evaluated results:
[tex]\[ \int_1^e \left(16x - \frac{5}{x}\right) \, dx = (8e^2 - 8) - 5 \][/tex]
Simplify the expression:
[tex]\[ 8e^2 - 8 - 5 = 8e^2 - 13 \][/tex]

So, the value of the integral is [tex]\(\boxed{8e^2 - 13}\)[/tex].

Thus, the correct choice is:
A. [tex]\(8e^2 - 13\)[/tex]