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Madi has \[tex]$8.80 in pennies and nickels. If there are twice as many nickels as pennies, how many pennies and nickels does Madi have?

Complete the equations below, where \( p \) stands for pennies and \( n \) stands for nickels.
\[
\begin{array}{c}
0.01p + 0.05n = 8.80 \\
n = 2p
\end{array}
\]

Reminder: A penny is worth \$[/tex]0.01 and a nickel is worth \$0.05.

Sagot :

To solve the given problem, let's start by defining the variables:

- Let [tex]\( p \)[/tex] represent the number of pennies.
- Let [tex]\( n \)[/tex] represent the number of nickels.

According to the problem, we have two pieces of information:
1. The total value of the pennies and nickels is $8.80.
2. There are twice as many nickels as there are pennies.

We can set up the following system of equations based on the given information:

1. The first equation comes from the total value of the pennies and nickels:
[tex]\[ 0.01p + 0.05n = 8.80 \][/tex]

2. The second equation comes from the relationship between the number of nickels and pennies:
[tex]\[ n = 2p \][/tex]

Now, let's solve these equations step-by-step.

### Step 1: Substitute the value of [tex]\( n \)[/tex] from the second equation into the first equation

From the second equation, we know:
[tex]\[ n = 2p \][/tex]

Substitute [tex]\( n \)[/tex] into the first equation:
[tex]\[ 0.01p + 0.05(2p) = 8.80 \][/tex]

### Step 2: Simplify the equation

Distribute the 0.05 through the parentheses:
[tex]\[ 0.01p + 0.10p = 8.80 \][/tex]

Combine like terms:
[tex]\[ 0.11p = 8.80 \][/tex]

### Step 3: Solve for [tex]\( p \)[/tex]

To isolate [tex]\( p \)[/tex], divide both sides of the equation by 0.11:
[tex]\[ p = \frac{8.80}{0.11} \][/tex]
[tex]\[ p = 80 \][/tex]

So, Madi has 80 pennies.

### Step 4: Solve for [tex]\( n \)[/tex]

Use the second equation to find [tex]\( n \)[/tex]:
[tex]\[ n = 2p \][/tex]
[tex]\[ n = 2 \times 80 \][/tex]
[tex]\[ n = 160 \][/tex]

So, Madi has 160 nickels.

### Solution:

Madi has 80 pennies and 160 nickels.

To summarize:
[tex]\[ \begin{array}{c} 0.01p + 0.05n = 8.80 \\ n = 2p \end{array} \][/tex]

The values are:
[tex]\[ p = 80, \quad n = 160 \][/tex]

Thus, Madi has 80 pennies and 160 nickels.

Answer:

80 pennies

160 nickles

Step-by-step explanation:

8.80 = p(0.01) + n(0.05)

n=2p

substitution

8.80=p(0.01) + 2p(0.05)

*100 to both sides for simplicity.

880=p+2p(5)

880=11p

80=p

80 pennies

160 nickles