At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

1. Which equation contains a difference of squares?

A. [tex]4x^2 - 80 = 0[/tex]

B. [tex]x^2 = 2[/tex]

C. [tex]9x^2 = 69[/tex]

D. [tex]36x^2 - 100 = 0[/tex]

Sagot :

To determine which of the given equations contains a difference of squares, we need to recall that an equation contains a difference of squares if it is of the form [tex]\(a^2 - b^2 = 0\)[/tex], which can be factored as [tex]\((a + b)(a - b) = 0\)[/tex].

Let's analyze each equation step-by-step:

1. Equation 1: [tex]\(4 x^2 - 80 = 0\)[/tex]

We can rewrite this equation as:
[tex]\[ 4 x^2 - 80 = 0 \][/tex]
By factoring out the common term:
[tex]\[ 4(x^2 - 20) = 0 \][/tex]
The expression inside the parenthesis, [tex]\(x^2 - 20\)[/tex], is not a difference of squares because [tex]\(20\)[/tex] is not a perfect square.

Thus, this equation does not contain a difference of squares.

2. Equation 2: [tex]\(x^2 = 2\)[/tex]

We rewrite this equation as:
[tex]\[ x^2 - 2 = 0 \][/tex]
The expression [tex]\(x^2 - 2\)[/tex] is not a difference of squares because [tex]\(2\)[/tex] is not a perfect square.

Thus, this equation does not contain a difference of squares.

3. Equation 3: [tex]\(9 x^2 = 69\)[/tex]

We rewrite this equation as:
[tex]\[ 9 x^2 - 69 = 0 \][/tex]
By factoring out the common term:
[tex]\[ 9 (x^2 - \frac{69}{9}) = 0 \][/tex]
Simplify the fraction:
[tex]\[ 9 (x^2 - \frac{23}{3}) = 0 \][/tex]
The expression inside the parenthesis, [tex]\(x^2 - \frac{23}{3}\)[/tex], is not a difference of squares because [tex]\(\frac{23}{3}\)[/tex] is not a perfect square.

Thus, this equation does not contain a difference of squares.

4. Equation 4: [tex]\(36 x^2 - 100 = 0\)[/tex]

We rewrite this equation as:
[tex]\[ 36 x^2 - 100 = 0 \][/tex]
By factoring or recognizing the structure:
[tex]\[ 36 x^2 - 100 = 0 \][/tex]
Recognize [tex]\(36 x^2\)[/tex] and [tex]\(100\)[/tex] are perfect squares:
[tex]\[ (6x)^2 - 10^2 = 0 \][/tex]
This is indeed a difference of squares, and can be factored as:
[tex]\[ (6x + 10)(6x - 10) = 0 \][/tex]

Thus, the equation [tex]\(36 x^2 - 100 = 0\)[/tex] contains a difference of squares. Therefore, the correct answer is:

[tex]\[ \boxed{4} \][/tex]