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Solve for [tex]$x$[/tex].

[tex]8(x-1) = -4x + 136[/tex]

A. [tex]x = 12[/tex]
B. [tex]x = 11[/tex]
C. [tex]x = \frac{181}{12}[/tex]
D. [tex]x = 36[/tex]

Sagot :

GinnyAnswer
Sure, let's solve the equation step by step.

The given equation is:
[tex]\[ 8(x-1) = -4x + 136 \][/tex]

1. Distribute the 8 on the left side:
[tex]\[ 8 \cdot x - 8 \cdot 1 = 8x - 8 \][/tex]
[tex]\[ 8x - 8 = -4x + 136 \][/tex]

2. Move all terms involving [tex]\( x \)[/tex] to one side and constants to the other side. Add [tex]\( 4x \)[/tex] to both sides:
[tex]\[ 8x + 4x - 8 = 136 \][/tex]
This simplifies to:
[tex]\[ 12x - 8 = 136 \][/tex]

3. Add 8 to both sides to isolate the term with [tex]\( x \)[/tex]:
[tex]\[ 12x - 8 + 8 = 136 + 8 \][/tex]
This simplifies to:
[tex]\[ 12x = 144 \][/tex]

4. Divide both sides by 12 to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{144}{12} \][/tex]
[tex]\[ x = 12 \][/tex]

So, the solution for [tex]\(x\)[/tex] is [tex]\( \boxed{12} \)[/tex].
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