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Write the equation [tex]2x^2 - 4x + 6 = 1[/tex] in standard form and then choose the value of "c."

A. 5
B. 2.5
C. 3

Sagot :

GinnyAnswer
Sure! Let's start with the equation given:

[tex]\[2x^2 - 4x + 6 = 1\][/tex]

We want to put this in the standard form of a quadratic equation, which is [tex]\(ax^2 + bx + c = 0\)[/tex].

1. Move the constant term on the right-hand side (which is 1) to the left-hand side of the equation. This can be done by subtracting 1 from both sides:

[tex]\[ 2x^2 - 4x + 6 - 1 = 0 \][/tex]

2. Simplify the left-hand side by combining the constants:

[tex]\[ 2x^2 - 4x + 5 = 0 \][/tex]

Now, the equation is in standard form, which is:

[tex]\[2x^2 - 4x + 5 = 0\][/tex]

In this standard form [tex]\(ax^2 + bx + c = 0\)[/tex], the value of the constant term [tex]\(c\)[/tex] is 5.

Therefore, the value of [tex]\(c\)[/tex] is:

[tex]\[ \boxed{5} \][/tex]
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