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Sagot :
Sure! Let's solve the given system of linear equations using the substitution method step-by-step.
### Part i:
Solve the following system of equations using the substitution method:
[tex]\[ \begin{cases} 3x - 2y = 5 \\ 2x + y = 8 \end{cases} \][/tex]
1. Solve the second equation for [tex]\( y \)[/tex]:
[tex]\[ 2x + y = 8 \quad \Rightarrow \quad y = 8 - 2x \][/tex]
2. Substitute [tex]\( y = 8 - 2x \)[/tex] into the first equation:
[tex]\[ 3x - 2(8 - 2x) = 5 \][/tex]
Simplify the equation:
[tex]\[ 3x - 16 + 4x = 5 \quad \Rightarrow \quad 7x - 16 = 5 \quad \Rightarrow \quad 7x = 21 \quad \Rightarrow \quad x = 3 \][/tex]
3. Substitute [tex]\( x = 3 \)[/tex] back into the equation [tex]\( y = 8 - 2x \)[/tex] to find [tex]\( y \)[/tex]:
[tex]\[ y = 8 - 2(3) \quad \Rightarrow \quad y = 8 - 6 \quad \Rightarrow \quad y = 2 \][/tex]
Therefore, the solution to the first system of equations is:
[tex]\[ (x, y) = (3, 2) \][/tex]
### Part ii:
Solve the following system of equations using the substitution method:
[tex]\[ \begin{cases} 7x - y = 14 \\ 8x - 2y = 16 \end{cases} \][/tex]
1. Solve the second equation for [tex]\( y \)[/tex]:
[tex]\[ 8x - 2y = 16 \quad \Rightarrow \quad -2y = 16 - 8x \quad \Rightarrow \quad y = \frac{8x - 16}{2} \quad \Rightarrow \quad y = 4x - 8 \][/tex]
2. Substitute [tex]\( y = 4x - 8 \)[/tex] into the first equation:
[tex]\[ 7x - (4x - 8) = 14 \][/tex]
Simplify the equation:
[tex]\[ 7x - 4x + 8 = 14 \quad \Rightarrow \quad 3x + 8 = 14 \quad \Rightarrow \quad 3x = 6 \quad \Rightarrow \quad x = 2 \][/tex]
3. Substitute [tex]\( x = 2 \)[/tex] back into the equation [tex]\( y = 4x - 8 \)[/tex] to find [tex]\( y \)[/tex]:
[tex]\[ y = 4(2) - 8 \quad \Rightarrow \quad y = 8 - 8 \quad \Rightarrow \quad y = 0 \][/tex]
Therefore, the solution to the second system of equations is:
[tex]\[ (x, y) = (2, 0) \][/tex]
### Summary of Solutions:
- For the first system: [tex]\((x, y) = (3, 2)\)[/tex]
- For the second system: [tex]\((x, y) = (2, 0)\)[/tex]
These solutions are found by following the step-by-step substitution method.
### Part i:
Solve the following system of equations using the substitution method:
[tex]\[ \begin{cases} 3x - 2y = 5 \\ 2x + y = 8 \end{cases} \][/tex]
1. Solve the second equation for [tex]\( y \)[/tex]:
[tex]\[ 2x + y = 8 \quad \Rightarrow \quad y = 8 - 2x \][/tex]
2. Substitute [tex]\( y = 8 - 2x \)[/tex] into the first equation:
[tex]\[ 3x - 2(8 - 2x) = 5 \][/tex]
Simplify the equation:
[tex]\[ 3x - 16 + 4x = 5 \quad \Rightarrow \quad 7x - 16 = 5 \quad \Rightarrow \quad 7x = 21 \quad \Rightarrow \quad x = 3 \][/tex]
3. Substitute [tex]\( x = 3 \)[/tex] back into the equation [tex]\( y = 8 - 2x \)[/tex] to find [tex]\( y \)[/tex]:
[tex]\[ y = 8 - 2(3) \quad \Rightarrow \quad y = 8 - 6 \quad \Rightarrow \quad y = 2 \][/tex]
Therefore, the solution to the first system of equations is:
[tex]\[ (x, y) = (3, 2) \][/tex]
### Part ii:
Solve the following system of equations using the substitution method:
[tex]\[ \begin{cases} 7x - y = 14 \\ 8x - 2y = 16 \end{cases} \][/tex]
1. Solve the second equation for [tex]\( y \)[/tex]:
[tex]\[ 8x - 2y = 16 \quad \Rightarrow \quad -2y = 16 - 8x \quad \Rightarrow \quad y = \frac{8x - 16}{2} \quad \Rightarrow \quad y = 4x - 8 \][/tex]
2. Substitute [tex]\( y = 4x - 8 \)[/tex] into the first equation:
[tex]\[ 7x - (4x - 8) = 14 \][/tex]
Simplify the equation:
[tex]\[ 7x - 4x + 8 = 14 \quad \Rightarrow \quad 3x + 8 = 14 \quad \Rightarrow \quad 3x = 6 \quad \Rightarrow \quad x = 2 \][/tex]
3. Substitute [tex]\( x = 2 \)[/tex] back into the equation [tex]\( y = 4x - 8 \)[/tex] to find [tex]\( y \)[/tex]:
[tex]\[ y = 4(2) - 8 \quad \Rightarrow \quad y = 8 - 8 \quad \Rightarrow \quad y = 0 \][/tex]
Therefore, the solution to the second system of equations is:
[tex]\[ (x, y) = (2, 0) \][/tex]
### Summary of Solutions:
- For the first system: [tex]\((x, y) = (3, 2)\)[/tex]
- For the second system: [tex]\((x, y) = (2, 0)\)[/tex]
These solutions are found by following the step-by-step substitution method.
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