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A delivered price (including attachments) of a crawler dozer tractor is [tex]$\$ 135,000$[/tex] with a residual value of [tex]35 \%[/tex]. The useful life of the tractor is 7,700 hours.

a. What is the total amount of depreciation allowed?
\[
\begin{tabular}{l|l}
\hline
\text{Total amount} & $\[tex]$ 87,750$[/tex] \\
\hline
\end{tabular}
\]

b. What is the amount of depreciation per hour?
Note: Round your answer to the nearest cent.
[tex]\[
\text{Amount of depreciation per hour:}
\][/tex]

c. If the tractor is operated five days a week for an average of 7.25 hours a day, what would be the depreciation for the first year?
[tex]\[
\text{Depreciation for the first year:}
\][/tex]


Sagot :

Let's solve the problem step-by-step.

### Part (a): Total Amount of Depreciation Allowed

Given data:
- Delivered price of the tractor: \[tex]$135,000 - Residual value percentage: 35% - Useful life: 7,700 hours First, calculate the residual value in dollars: \[ \text{Residual value in dollars} = \text{Delivered price} \times \left(\frac{\text{Residual value percentage}}{100}\right) = 135,000 \times 0.35 = \$[/tex]47,250
\]

Next, calculate the total amount of depreciation allowed by subtracting the residual value from the delivered price:

[tex]\[ \text{Total depreciation} = \text{Delivered price} - \text{Residual value in dollars} = 135,000 - 47,250 = \$87,750 \][/tex]

Hence, the total amount of depreciation allowed is [tex]\( \$87,750 \)[/tex].

### Part (b): Amount of Depreciation Per Hour

To find the depreciation per hour, divide the total depreciation by the useful life in hours:

[tex]\[ \text{Depreciation per hour} = \frac{\text{Total depreciation}}{\text{Useful life in hours}} = \frac{87,750}{7,700} \approx \$11.40 \text{ (rounded to the nearest cent)} \][/tex]

### Part (c): Depreciation for the First Year

The tractor is operated:
- 5 days a week
- An average of 7.25 hours per day

First, calculate the total number of hours the tractor is operated in a week:

[tex]\[ \text{Total hours per week} = 5 \times 7.25 = 36.25 \text{ hours} \][/tex]

Next, calculate the total number of hours the tractor is operated in a year (assuming 52 weeks in a year):

[tex]\[ \text{Total hours per year} = 36.25 \times 52 = 1,885 \text{ hours} \][/tex]

Finally, calculate the depreciation for the first year by multiplying the total hours operated in the first year by the depreciation per hour:

[tex]\[ \text{Depreciation for the first year} = \text{Total hours per year} \times \text{Depreciation per hour} = 1,885 \times 11.40 \approx \$21,481.66 \][/tex]

### Summary of Results

(a) Total amount of depreciation allowed: \[tex]$87,750 (b) Amount of depreciation per hour: \$[/tex]11.40

(c) Depreciation for the first year: \$21,481.66
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