To determine the concentration of sodium ions in a 0.35 M sodium phosphate (NaPO₄) solution, follow these steps:
1. Understand the Dissociation of Sodium Phosphate (NaPO₄):
Sodium phosphate dissociates completely in water to produce sodium (Na⁺) ions and phosphate (PO₄³⁻) ions. The balanced dissociation equation is:
[tex]\[
\text{NaPO₄} \rightarrow 3\text{Na}^+ + \text{PO₄}^{3-}
\][/tex]
2. Determine the Mole Ratio:
From the dissociation equation, we can observe that one molecule of sodium phosphate produces three sodium ions. This gives us a mole ratio of 1:3 between sodium phosphate and sodium ions.
3. Calculate the Concentration of Sodium Ions:
Given that the concentration of sodium phosphate is 0.35 M, and knowing the mole ratio from step 2, we can calculate the concentration of sodium ions.
[tex]\[
\text{Concentration of Na⁺ ions} = \text{Concentration of NaPO₄} \times \text{Number of Na⁺ ions per NaPO₄ molecule}
\][/tex]
[tex]\[
\text{Concentration of Na⁺ ions} = 0.35\, \text{M} \times 3
\][/tex]
4. Compute the Result:
[tex]\[
\text{Concentration of Na⁺ ions} = 1.0499999999999998\, \text{M}
\][/tex]
Therefore, the concentration of sodium ions in a 0.35 M sodium phosphate solution is approximately 1.05 M.
