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Write the following expression as a sum and/or difference of logarithms. Express powers as factors.

[tex]\[ \ln[e(x + 3)] \][/tex]

[tex]\[
\ln[e(x + 3)] = \boxed{\quad}
\][/tex]

(Simplify your answer.)


Sagot :

To simplify the given expression [tex]\(\ln[e(x + 3)]\)[/tex], we can use properties of logarithms and exponentials. Here are the steps to reach the solution:

1. Understanding the Properties of Logarithms:
- One of the key properties of logarithms is that the logarithm of a product is the sum of logarithms: [tex]\(\ln(AB) = \ln(A) + \ln(B)\)[/tex].
- Also, the natural logarithm of the base [tex]\(e\)[/tex] is 1: [tex]\(\ln(e) = 1\)[/tex].

2. Break Down the Expression:
- The expression inside the logarithm is a product of [tex]\(e\)[/tex] and [tex]\((x + 3)\)[/tex].
- Using the product property of logarithms, we can separate the logarithm of a product into a sum of two logarithms:
[tex]\[ \ln[e(x + 3)] = \ln[e] + \ln[x + 3]. \][/tex]

3. Simplify the Logarithm:
- We know that [tex]\(\ln(e) = 1\)[/tex].

4. Combine the Results:
- So, we replace [tex]\(\ln(e)\)[/tex] with 1 in our expression:
[tex]\[ \ln[e(x + 3)] = 1 + \ln[x + 3]. \][/tex]

Therefore, the simplified form of [tex]\(\ln[e(x + 3)]\)[/tex] is:
[tex]\[ \boxed{1 + \ln(x + 3)} \][/tex]
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