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Write the following expression as a sum and/or difference of logarithms. Express powers as factors.

[tex]\ln (e x)[/tex]

[tex]\ln (e x) = \square[/tex]

(Simplify your answer.)


Sagot :

To simplify [tex]\(\ln (e x)\)[/tex], we can use the properties of logarithms. One essential property is:

[tex]\[ \ln(a \cdot b) = \ln(a) + \ln(b) \][/tex]

So, in the given expression [tex]\(\ln (e x)\)[/tex], we can decompose it as follows:

1. Identify the components inside the logarithm. Here [tex]\(a = e\)[/tex] and [tex]\(b = x\)[/tex].

2. Apply the logarithm product rule:

[tex]\[ \ln (e x) = \ln(e) + \ln(x) \][/tex]

3. Recognize that [tex]\(\ln(e) = 1\)[/tex] because [tex]\(e\)[/tex] is the base of the natural logarithm:

[tex]\[ \ln(e) = 1 \][/tex]

4. Substitute [tex]\(\ln(e)\)[/tex] with 1 in the equation:

[tex]\[ \ln(e x) = 1 + \ln(x) \][/tex]

Therefore, the expression [tex]\(\ln (e x)\)[/tex] simplifies to:

[tex]\[ 1 + \ln(x) \][/tex]
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