Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To determine which function among [tex]\( g, h, \)[/tex] and [tex]\( k \)[/tex] has the least minimum value, we need to analyze the minimum values of each function over the interval from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex].
1. Evaluating [tex]\( g(x) \)[/tex]:
Given the table of values for [tex]\( g(x) \)[/tex]:
[tex]\[ \begin{array}{|c|c|} \hline x & g(x) \\ \hline -2 & 76 \\ -1 & 11 \\ 0 & -4 \\ 1 & -5 \\ 2 & -4 \\ 3 & 11 \\ \hline \end{array} \][/tex]
The minimum value of [tex]\( g(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(-5\)[/tex].
2. Evaluating [tex]\( h(x) \)[/tex]:
The function [tex]\( h(x) \)[/tex] is defined as:
[tex]\[ h(x) = 2(x - 1)^2 \][/tex]
To find the minimum value of [tex]\( h(x) \)[/tex] over the interval [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex]:
[tex]\[ \begin{aligned} h(-2) &= 2(-2 - 1)^2 = 2( -3)^2 = 2 \times 9 = 18, \\ h(-1) &= 2(-1 - 1)^2 = 2( -2)^2 = 2 \times 4 = 8, \\ h(0) &= 2(0 - 1)^2 = 2( -1)^2 = 2 \times 1 = 2, \\ h(1) &= 2(1 - 1)^2 = 2( 0)^2 = 2 \times 0 = 0, \\ h(2) &= 2(2 - 1)^2 = 2( 1)^2 = 2 \times 1 = 2, \\ h(3) &= 2(3 - 1)^2 = 2( 2)^2 = 2 \times 4 = 8. \end{aligned} \][/tex]
The minimum value of [tex]\( h(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(0\)[/tex].
3. Evaluating [tex]\( k(x) \)[/tex]:
The function [tex]\( k(x) \)[/tex] is defined as:
[tex]\[ k(x) = x^4 + 2x^2 + 8x - 4 \][/tex]
To find the minimum value of [tex]\( k(x) \)[/tex] over the interval [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex]:
[tex]\[ \begin{aligned} k(-2) &= (-2)^4 + 2(-2)^2 + 8(-2) - 4 = 16 + 8 - 16 - 4 = 4, \\ k(-1) &= (-1)^4 + 2(-1)^2 + 8(-1) - 4 = 1 + 2 - 8 - 4 = -9, \\ k(0) &= 0^4 + 2(0)^2 + 8(0) - 4 = -4, \\ k(1) &= 1^4 + 2(1)^2 + 8(1) - 4 = 1 + 2 + 8 - 4 = 7, \\ k(2) &= 2^4 + 2(2)^2 + 8(2) - 4 = 16 + 8 + 16 - 4 = 36, \\ k(3) &= 3^4 + 2(3)^2 + 8(3) - 4 = 81 + 18 + 24 - 4 = 119. \end{aligned} \][/tex]
The minimum value of [tex]\( k(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(-9\)[/tex].
Comparing the minimum values:
- Minimum of [tex]\( g(x) \)[/tex]: [tex]\(-5\)[/tex]
- Minimum of [tex]\( h(x) \)[/tex]: [tex]\(0\)[/tex]
- Minimum of [tex]\( k(x) \)[/tex]: [tex]\(-9\)[/tex]
The function that has the least minimum value is [tex]\( k \)[/tex].
So, the correct answer is:
The function that has the least minimum value is function [tex]\( \boxed{k} \)[/tex].
1. Evaluating [tex]\( g(x) \)[/tex]:
Given the table of values for [tex]\( g(x) \)[/tex]:
[tex]\[ \begin{array}{|c|c|} \hline x & g(x) \\ \hline -2 & 76 \\ -1 & 11 \\ 0 & -4 \\ 1 & -5 \\ 2 & -4 \\ 3 & 11 \\ \hline \end{array} \][/tex]
The minimum value of [tex]\( g(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(-5\)[/tex].
2. Evaluating [tex]\( h(x) \)[/tex]:
The function [tex]\( h(x) \)[/tex] is defined as:
[tex]\[ h(x) = 2(x - 1)^2 \][/tex]
To find the minimum value of [tex]\( h(x) \)[/tex] over the interval [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex]:
[tex]\[ \begin{aligned} h(-2) &= 2(-2 - 1)^2 = 2( -3)^2 = 2 \times 9 = 18, \\ h(-1) &= 2(-1 - 1)^2 = 2( -2)^2 = 2 \times 4 = 8, \\ h(0) &= 2(0 - 1)^2 = 2( -1)^2 = 2 \times 1 = 2, \\ h(1) &= 2(1 - 1)^2 = 2( 0)^2 = 2 \times 0 = 0, \\ h(2) &= 2(2 - 1)^2 = 2( 1)^2 = 2 \times 1 = 2, \\ h(3) &= 2(3 - 1)^2 = 2( 2)^2 = 2 \times 4 = 8. \end{aligned} \][/tex]
The minimum value of [tex]\( h(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(0\)[/tex].
3. Evaluating [tex]\( k(x) \)[/tex]:
The function [tex]\( k(x) \)[/tex] is defined as:
[tex]\[ k(x) = x^4 + 2x^2 + 8x - 4 \][/tex]
To find the minimum value of [tex]\( k(x) \)[/tex] over the interval [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex]:
[tex]\[ \begin{aligned} k(-2) &= (-2)^4 + 2(-2)^2 + 8(-2) - 4 = 16 + 8 - 16 - 4 = 4, \\ k(-1) &= (-1)^4 + 2(-1)^2 + 8(-1) - 4 = 1 + 2 - 8 - 4 = -9, \\ k(0) &= 0^4 + 2(0)^2 + 8(0) - 4 = -4, \\ k(1) &= 1^4 + 2(1)^2 + 8(1) - 4 = 1 + 2 + 8 - 4 = 7, \\ k(2) &= 2^4 + 2(2)^2 + 8(2) - 4 = 16 + 8 + 16 - 4 = 36, \\ k(3) &= 3^4 + 2(3)^2 + 8(3) - 4 = 81 + 18 + 24 - 4 = 119. \end{aligned} \][/tex]
The minimum value of [tex]\( k(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(-9\)[/tex].
Comparing the minimum values:
- Minimum of [tex]\( g(x) \)[/tex]: [tex]\(-5\)[/tex]
- Minimum of [tex]\( h(x) \)[/tex]: [tex]\(0\)[/tex]
- Minimum of [tex]\( k(x) \)[/tex]: [tex]\(-9\)[/tex]
The function that has the least minimum value is [tex]\( k \)[/tex].
So, the correct answer is:
The function that has the least minimum value is function [tex]\( \boxed{k} \)[/tex].
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.