Answered

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Which whole numbers less than 10 are solutions of [tex]$4x - 8 \leq 4$[/tex]?

A. [tex]0, 1, 2, 3[/tex]

B. [tex]1, 2, 3, 4[/tex]

C. [tex]0, 2, 4, 6[/tex]

D. [tex]1, 2, 3, 5[/tex]

Sagot :

GinnyAnswer
To determine which whole numbers less than 10 satisfy the inequality [tex]\( 4x - 8 \leq 4 \)[/tex], we can solve the inequality step-by-step.

1. Start with the given inequality:
[tex]\[ 4x - 8 \leq 4 \][/tex]

2. Add 8 to both sides of the inequality to isolate the term with the variable [tex]\( x \)[/tex]:
[tex]\[ 4x - 8 + 8 \leq 4 + 8 \][/tex]
[tex]\[ 4x \leq 12 \][/tex]

3. Divide both sides of the inequality by 4 to solve for [tex]\( x \)[/tex]:
[tex]\[ \frac{4x}{4} \leq \frac{12}{4} \][/tex]
[tex]\[ x \leq 3 \][/tex]

Thus, the solutions to the inequality are the whole numbers less than or equal to 3.

Considering that [tex]\( x \)[/tex] must be less than 10, we list the whole numbers that are less than or equal to 3:
[tex]\[ 0, 1, 2, 3 \][/tex]

Therefore, the correct answer is:
[tex]\[ \boxed{0, 1, 2, 3} \][/tex]
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