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Solve the equation [tex]71y = 14(5y + 29)[/tex].

[tex]y = 1[/tex]

Sagot :

GinnyAnswer
To solve the equation [tex]\(71y = 14(5y + 29)\)[/tex], follow these steps:

1. Distribute the 14 on the right side of the equation:
[tex]\[ 14(5y + 29) = 14 \cdot 5y + 14 \cdot 29 \][/tex]
Simplify:
[tex]\[ 14 \cdot 5y = 70y \][/tex]
[tex]\[ 14 \cdot 29 = 406 \][/tex]
So,
[tex]\[ 14(5y + 29) = 70y + 406 \][/tex]

2. Now, set the left side equal to the right side:
[tex]\[ 71y = 70y + 406 \][/tex]

3. Subtract [tex]\(70y\)[/tex] from both sides to isolate [tex]\(y\)[/tex]:
[tex]\[ 71y - 70y = 406 \][/tex]
Simplify the left side:
[tex]\[ y = 406 \][/tex]

The value of [tex]\(y\)[/tex] that satisfies the equation is:
[tex]\[ y = 406 \][/tex]
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