Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
To balance the molecular equation for the reaction between the weak base sodium hypochlorite ([tex]\(\text{NaClO (aq)}\)[/tex]) and the strong acid sulfuric acid ([tex]\(\text{H}_2\text{SO}_4\text{(aq)}\)[/tex]), let's follow these steps:
1. List the reacting compounds and their respective elements:
- [tex]\(\text{NaClO}\)[/tex]
- Sodium (Na): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Hydrogen (H): 2
- Sulfur (S): 1
- Oxygen (O): 4
2. Identify the products and balance each element:
- Products: [tex]\(\text{HClO} \text{ (aq)}\)[/tex] and [tex]\(\text{NaHSO}_4 \text{ (aq)}\)[/tex]
- [tex]\(\text{HClO}\)[/tex]
- Hydrogen (H): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{NaHSO}_4\)[/tex]
- Sodium (Na): 1
- Hydrogen (H): 1
- Sulfur (S): 1
- Oxygen (O): 4
3. Ensure both sides of the reaction have equal numbers of atoms for each element:
- Left side (Reactants):
- Sodium (Na): 1 from [tex]\(\text{NaClO}\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{NaClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{NaClO}\)[/tex] + 4 from [tex]\(\text{H}_2\text{SO}_4\)[/tex] = 5
- Hydrogen (H): 2 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Sulfur (S): 1 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Right side (Products):
- Sodium (Na): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{HClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{HClO}\)[/tex] + 4 from [tex]\(\text{NaHSO}_4\)[/tex] = 5
- Hydrogen (H): 1 from [tex]\(\text{HClO}\)[/tex] + 1 from [tex]\(\text{NaHSO}_4\)[/tex] = 2
- Sulfur (S): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
Since each element has the same number of atoms on both sides of the reaction equation, the equation is balanced.
4. Write the balanced equation:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
Thus, the balanced molecular reaction for the given weak base and strong acid is:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
1. List the reacting compounds and their respective elements:
- [tex]\(\text{NaClO}\)[/tex]
- Sodium (Na): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Hydrogen (H): 2
- Sulfur (S): 1
- Oxygen (O): 4
2. Identify the products and balance each element:
- Products: [tex]\(\text{HClO} \text{ (aq)}\)[/tex] and [tex]\(\text{NaHSO}_4 \text{ (aq)}\)[/tex]
- [tex]\(\text{HClO}\)[/tex]
- Hydrogen (H): 1
- Chlorine (Cl): 1
- Oxygen (O): 1
- [tex]\(\text{NaHSO}_4\)[/tex]
- Sodium (Na): 1
- Hydrogen (H): 1
- Sulfur (S): 1
- Oxygen (O): 4
3. Ensure both sides of the reaction have equal numbers of atoms for each element:
- Left side (Reactants):
- Sodium (Na): 1 from [tex]\(\text{NaClO}\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{NaClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{NaClO}\)[/tex] + 4 from [tex]\(\text{H}_2\text{SO}_4\)[/tex] = 5
- Hydrogen (H): 2 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Sulfur (S): 1 from [tex]\(\text{H}_2\text{SO}_4\)[/tex]
- Right side (Products):
- Sodium (Na): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
- Chlorine (Cl): 1 from [tex]\(\text{HClO}\)[/tex]
- Oxygen (O): 1 from [tex]\(\text{HClO}\)[/tex] + 4 from [tex]\(\text{NaHSO}_4\)[/tex] = 5
- Hydrogen (H): 1 from [tex]\(\text{HClO}\)[/tex] + 1 from [tex]\(\text{NaHSO}_4\)[/tex] = 2
- Sulfur (S): 1 from [tex]\(\text{NaHSO}_4\)[/tex]
Since each element has the same number of atoms on both sides of the reaction equation, the equation is balanced.
4. Write the balanced equation:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
Thus, the balanced molecular reaction for the given weak base and strong acid is:
[tex]\[ \text{NaClO (aq)} + \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{HClO (aq)} + \text{NaHSO}_4\text{(aq)} \][/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.