Answered

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A rectangular field is twice as long as it is wide. If the perimeter of the athletic field is 120 yards, what are the dimensions

Sagot :

Heather

Answer: 40 yards long by 20 yards wide.

Step-by-step explanation:

      Let x be the width of this rectangular field. This means that x is the width and 2x is the length since it's twice as long as it is wide.

Perimeter:

      l + l + w + w = P

Substitute known values:

      2x + 2x + x + x = 120

Combine like terms:

      6x = 120

Divide both sides of the equation by 6:

      x = 20 yards wide

Find the length:

      2x = 2 * 20 = 40 yards long

Eloquence

Answer:

40 cm and 20 cm

Step-by-step explanation:

To find the dimensions of the field, use the perimeter formula.

Let's call the width w. Then, the length is 2*w, since it's twice as much as the width.

We know that the perimeter is 120 yards.

The perimeter formula is: [tex]\boldsymbol{\sf P=2(l+w)}[/tex] where l = length

Substitute our values.

[tex]\sf 120=2(2w + 2)[/tex]

Solve for w.

[tex]\sf 120=2(3w)[/tex]

[tex]\sf 120=6w[/tex]

Divide both sides by 6.

[tex]\sf w=20[/tex]

Don't forget to multiply it by 2 to find the length.

[tex]\sf 20*2=40\:cm[/tex]

Therefore, the dimensions of the field are 40 cm and 20 cm.

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