Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

What is the midpoint of the [tex]\( x \)[/tex]-intercepts of [tex]\( f(x) = (x-2)(x-4) \)[/tex]?

A. [tex]\((-3,0)\)[/tex]

B. [tex]\((-1,0)\)[/tex]

C. [tex]\((1,0)\)[/tex]

D. [tex]\((3,0)\)[/tex]


Sagot :

To determine the midpoint of the [tex]\( x \)[/tex]-intercepts of the function [tex]\( f(x) = (x - 2)(x - 4) \)[/tex], follow these steps:

1. Identify the [tex]\( x \)[/tex]-intercepts:
The [tex]\( x \)[/tex]-intercepts occur where the function [tex]\( f(x) \)[/tex] equals zero. Thus, we need to solve [tex]\( (x - 2)(x - 4) = 0 \)[/tex].

Setting each factor equal to zero gives us the [tex]\( x \)[/tex]-intercepts:
[tex]\[ x - 2 = 0 \quad \Rightarrow \quad x = 2 \][/tex]
[tex]\[ x - 4 = 0 \quad \Rightarrow \quad x = 4 \][/tex]
So, the [tex]\( x \)[/tex]-intercepts are [tex]\( x = 2 \)[/tex] and [tex]\( x = 4 \)[/tex].

2. Calculate the midpoint:
The midpoint of two points [tex]\( a \)[/tex] and [tex]\( b \)[/tex] on the number line is given by [tex]\( \frac{a + b}{2} \)[/tex].

Substituting [tex]\( a = 2 \)[/tex] and [tex]\( b = 4 \)[/tex]:
[tex]\[ \text{Midpoint} = \frac{2 + 4}{2} = \frac{6}{2} = 3 \][/tex]
Therefore, the coordinates of the midpoint are [tex]\( (3,0) \)[/tex].

So, the correct answer is:

[tex]\[ \boxed{(3,0)} \][/tex]