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Which point is an [tex]$x$[/tex]-intercept of the quadratic function [tex]f(x) = (x + 6)(x - 3)[/tex]?

A. [tex]\((0, 6)\)[/tex]

B. [tex]\((0, -6)\)[/tex]

C. [tex]\((6, 0)\)[/tex]

D. [tex]\((-6, 0)\)[/tex]

Sagot :

To determine the [tex]$x$[/tex]-intercepts of the quadratic function [tex]\( f(x) = (x+6)(x-3) \)[/tex], you need to find the values of [tex]\( x \)[/tex] where the function equals zero. This is achieved by setting [tex]\( f(x) = 0 \)[/tex] and solving for [tex]\( x \)[/tex].

1. Start with the given function:
[tex]\[ f(x) = (x+6)(x-3) \][/tex]

2. Set the function equal to zero to find the [tex]$x$[/tex]-intercepts:
[tex]\[ (x+6)(x-3) = 0 \][/tex]

3. Use the Zero Product Property, which states that if a product of factors is zero, at least one of the factors must be zero. Therefore, set each factor equal to zero and solve for [tex]\( x \)[/tex]:
[tex]\[ x + 6 = 0 \quad \text{or} \quad x - 3 = 0 \][/tex]

4. Solve each equation separately:
[tex]\[ x + 6 = 0 \quad \Rightarrow \quad x = -6 \][/tex]
[tex]\[ x - 3 = 0 \quad \Rightarrow \quad x = 3 \][/tex]

So, the [tex]$x$[/tex]-intercepts of the function are:
[tex]\[ (-6, 0) \quad \text{and} \quad (3, 0) \][/tex]

Among the given choices, the point [tex]\((-6, 0)\)[/tex] is listed. Therefore, the [tex]$x$[/tex]-intercept of the quadratic function [tex]\( f(x) = (x+6)(x-3) \)[/tex] that matches one of the given options is:
[tex]\[ (-6, 0) \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{(-6, 0)} \][/tex]