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What volume (in L) of a 0.724 M NaI solution contains 0.405 mol of NaI?

Sagot :

GinnyAnswer
Sure, let's solve this step-by-step.

Step 1: Understand the problem.
We are given the molarity (M) of the NaI solution and the number of moles (mol) of NaI dissolved in the solution. We need to find the volume (V) of the solution in liters (L).

Step 2: Identify the relationship between molarity, moles, and volume.
Molarity (M) is defined as the number of moles of solute (n) per liter of solution (V). The formula is:
[tex]\[ M = \frac{n}{V} \][/tex]

Step 3: Rearrange the formula to solve for volume (V).
[tex]\[ V = \frac{n}{M} \][/tex]
where:
- [tex]\( n \)[/tex] is the number of moles,
- [tex]\( M \)[/tex] is the molarity.

Step 4: Substitute the given values into the formula.
We have:
- [tex]\( n = 0.405 \, \text{mol} \)[/tex]
- [tex]\( M = 0.724 \, \text{M} \)[/tex]

So,
[tex]\[ V = \frac{0.405 \, \text{mol}}{0.724 \, \text{M}} \][/tex]

Step 5: Calculate the volume.
[tex]\[ V = 0.5593922651933703 \, \text{L} \][/tex]

Therefore, the volume of the 0.724 M NaI solution that contains 0.405 mol of NaI is approximately 0.559 L.
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