Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

What volume (in L) of a 0.724 M NaI solution contains 0.405 mol of NaI?

Sagot :

Sure, let's solve this step-by-step.

Step 1: Understand the problem.
We are given the molarity (M) of the NaI solution and the number of moles (mol) of NaI dissolved in the solution. We need to find the volume (V) of the solution in liters (L).

Step 2: Identify the relationship between molarity, moles, and volume.
Molarity (M) is defined as the number of moles of solute (n) per liter of solution (V). The formula is:
[tex]\[ M = \frac{n}{V} \][/tex]

Step 3: Rearrange the formula to solve for volume (V).
[tex]\[ V = \frac{n}{M} \][/tex]
where:
- [tex]\( n \)[/tex] is the number of moles,
- [tex]\( M \)[/tex] is the molarity.

Step 4: Substitute the given values into the formula.
We have:
- [tex]\( n = 0.405 \, \text{mol} \)[/tex]
- [tex]\( M = 0.724 \, \text{M} \)[/tex]

So,
[tex]\[ V = \frac{0.405 \, \text{mol}}{0.724 \, \text{M}} \][/tex]

Step 5: Calculate the volume.
[tex]\[ V = 0.5593922651933703 \, \text{L} \][/tex]

Therefore, the volume of the 0.724 M NaI solution that contains 0.405 mol of NaI is approximately 0.559 L.