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Drag each tile to the correct box. Not all tiles will be used.

Arrange the steps to solve this system of linear equations in the correct sequence.
[tex]\[
\begin{array}{l}
x+y=-2 \\
2x-3y=-9
\end{array}
\][/tex]

1. Multiply the first equation by 3 to get [tex]$3x + 3y = -6$[/tex].
2. Subtract [tex]$3x + 3y = -6$[/tex] (obtained in step 1) from [tex]$2x - 3y = -9$[/tex] to solve for [tex]$x$[/tex].
3. Substitute the value of [tex]$x$[/tex] in the first equation [tex]$(x + y = -2)$[/tex] to get [tex]$y = 1$[/tex].
4. The solution for the system of equations is [tex]$(-3, 1)$[/tex].

Unused tiles:
[tex]\[
x = -15
\][/tex]

Sagot :

GinnyAnswer
To solve the given system of linear equations:
[tex]\[ \begin{array}{l} x + y = -2 \\ 2x - 3y = -9 \end{array} \][/tex]

Follow these steps in the correct sequence:

1. Substitute the value of [tex]\( x \)[/tex] from the first equation [tex]\( (x + y = -2) \)[/tex] to solve for [tex]\( y \)[/tex].

2. Solve for [tex]\( y \)[/tex].

3. The solution for the system of equations is [tex]\((-3, 1)\)[/tex].

Now, let's substitute the steps:

1. Substitute the value of [tex]\( x \)[/tex] from the first equation [tex]\( (x + y = -2) \)[/tex] to solve for [tex]\( y \)[/tex]:
[tex]\[ x = -2 - y \][/tex]

2. Substitute [tex]\( x = -2 - y \)[/tex] into the second equation [tex]\( (2x - 3y = -9) \)[/tex]:
[tex]\[ 2(-2 - y) - 3y = -9 \][/tex]
Simplify and solve for [tex]\( y \)[/tex]:
[tex]\[ -4 - 2y - 3y = -9 \\ -5y - 4 = -9 \\ -5y = -5 \\ y = 1 \][/tex]

3. Substitute [tex]\( y = 1 \)[/tex] back into the first equation [tex]\( (x + 1 = -2) \)[/tex]:
[tex]\[ x + 1 = -2 \\ x = -2 - 1 \\ x = -3 \][/tex]

Thus, the solution for the system of equations is [tex]\( (x, y) = (-3, 1) \)[/tex].

So, the correct final step is:
- The solution for the system of equations is [tex]\((-3, 1)\)[/tex].
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