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Sagot :
To determine the probability that you randomly pick a month with exactly 30 days, let's go through the steps:
1. Understand the total number of months in a year:
- There are 12 months in a year.
2. Identify the months with exactly 30 days:
- The months with exactly 30 days are April, June, September, and November. This gives us a total of 4 months.
3. Calculate the probability:
- Probability is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
- Here, the favorable outcomes are the 4 months with 30 days.
- The total possible outcomes are the 12 months in the year.
Thus, the probability [tex]\( P \)[/tex] that a randomly chosen month has exactly 30 days is given by:
[tex]\[ P = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{4}{12} \][/tex]
Simplifying this fraction:
[tex]\[ \frac{4}{12} = \frac{1}{3} \][/tex]
So, the probability is [tex]\( \frac{1}{3} \)[/tex].
Therefore, the correct answer is:
D. [tex]\(\frac{1}{3}\)[/tex]
1. Understand the total number of months in a year:
- There are 12 months in a year.
2. Identify the months with exactly 30 days:
- The months with exactly 30 days are April, June, September, and November. This gives us a total of 4 months.
3. Calculate the probability:
- Probability is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
- Here, the favorable outcomes are the 4 months with 30 days.
- The total possible outcomes are the 12 months in the year.
Thus, the probability [tex]\( P \)[/tex] that a randomly chosen month has exactly 30 days is given by:
[tex]\[ P = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{4}{12} \][/tex]
Simplifying this fraction:
[tex]\[ \frac{4}{12} = \frac{1}{3} \][/tex]
So, the probability is [tex]\( \frac{1}{3} \)[/tex].
Therefore, the correct answer is:
D. [tex]\(\frac{1}{3}\)[/tex]
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