Sure, let's work through the given question step-by-step.
### Step 1: Understanding the Problem
We have two parts in the problem:
1. h. 11 anylate 14.
2. 6. [tex]$1101 = 110 \%$[/tex]
### Step 2: Decoding the Expressions
#### Part h: 11 anylate 14
Let's assume "11" stands for the binary representation of this number and "14" is already in decimal form. We will need to convert the binary number "11" into decimal.
- Binary number: 11
- Decimal equivalent: [tex]\( 1 \times 2^1 + 1 \times 2^0 = 2 + 1 = 3 \)[/tex]
Next, taking the decimal value of "14" as it is.
Next, let's express these values where:
- [tex]\(3\)[/tex] is derived from binary "11".
- The decimal value is [tex]\(14\)[/tex].
However, instead of any arithmetic operation here, based on natural assumption and conveyed instructions, we interpret "anylate" as an operation that would allow both binary and decimal values to remain.
Thus, this results in:
Final values from part h:
- Binary "11" to decimal -> 3
- Decimal 14 -> 14
#### Part 2: [tex]$1101 = 110 \%$[/tex]
Let's break down this part by converting the binary representations into their decimal equivalents:
- For [tex]\(1101\)[/tex] (binary [tex]\(1101\)[/tex]) to decimal:
- [tex]\( 1 \times 2^3 + 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 8 + 4 + 0 + 1 = 13 \)[/tex]
- For [tex]\(110\% \)[/tex] (which appears as "110" in binary under percentage):
- Discard the percentage symbol and treat "110" as binary:
- [tex]\( 1 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 = 4 + 2 + 0 = 6 \)[/tex]
### Step 3: Summarize the Results:
Given these conversions, we arrive at:
1. The decimal representation '11 anylate 14' gives us two numbers: 3, and 14.
2. The operation '$1101 = 110 \%' provides us with two numbers: 13 and 6.
Thus, we have:
- [tex]\(13\)[/tex] from binary "1101".
- [tex]\(6\)[/tex] from binary "110".
Final combined output from both parts is: [tex]\( (13, 6, 3, 14) \)[/tex].
But keeping aligned to common hierarchy primarily derived values remain:
h. "11 anylate 14 provides 3 juxtaposed with 14."
6. "1101 = 13 \% has decimal effective value pairing 6."
Refined combined input produces (13, 6), with 3 and 14 remain juxtaposed equivalently.
