Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To find the simple interest owed when [tex]$330 is borrowed at an interest rate of 7.9% for 10 years, we use the formula for simple interest:
\[ \text{Simple Interest} = P \times r \times t \]
where:
- \( P \) is the principal amount (initial amount borrowed).
- \( r \) is the annual interest rate (as a decimal).
- \( t \) is the time the money is borrowed for, in years.
Given the values:
- Principal amount, \( P = 330 \) dollars.
- Annual interest rate, \( r = 7.9\% \) (which is \( 7.9/100 = 0.079 \) as a decimal).
- Time, \( t = 10 \) years.
Let's plug in these values into the formula:
1. Convert the interest rate from a percentage to a decimal:
\[ r = \frac{7.9}{100} = 0.079 \]
2. Multiply the principal amount by the interest rate and the time:
\[ \text{Simple Interest} = 330 \times 0.079 \times 10 \]
3. Calculate the multiplication:
\[ \text{Simple Interest} = 330 \times 0.079 \times 10 = 260.7 \]
Therefore, the simple interest owed is $[/tex]260.7.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.