Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
To solve for [tex]\(i^3\)[/tex] using the properties of imaginary numbers and exponents, follow these steps:
1. Understanding [tex]\(i\)[/tex] and its powers:
- Recall that [tex]\(i\)[/tex] is the imaginary unit, defined by [tex]\(i^2 = -1\)[/tex].
2. Calculate [tex]\(i^2\)[/tex]:
- By definition, [tex]\(i^2 = -1\)[/tex].
3. Exponentiation Law:
- Use the property of exponents: [tex]\(i^3 = (i^2) \cdot i\)[/tex].
4. Calculate [tex]\(i^3\)[/tex]:
- Substitute [tex]\(i^2 = -1\)[/tex] into the expression for [tex]\(i^3\)[/tex]:
[tex]\[ i^3 = (i^2) \cdot i = (-1) \cdot i = -i \][/tex]
5. Imaginary Number Form:
- Writing in the form of complex numbers, where the real part is 0:
[tex]\[ -i = 0 - 1i \][/tex]
So, the calculations give us:
- [tex]\(i^2\)[/tex] is [tex]\(-1\)[/tex]
- [tex]\(i^3\)[/tex] is [tex]\(-i\)[/tex] or represented as [tex]\(0 - 1i\)[/tex].
Thus, we have:
[tex]\[ i^2 = -1 + 0j \][/tex]
[tex]\[ i^3 = -0 - 1j \][/tex]
These results match our understanding of the powers of the imaginary unit [tex]\(i\)[/tex].
1. Understanding [tex]\(i\)[/tex] and its powers:
- Recall that [tex]\(i\)[/tex] is the imaginary unit, defined by [tex]\(i^2 = -1\)[/tex].
2. Calculate [tex]\(i^2\)[/tex]:
- By definition, [tex]\(i^2 = -1\)[/tex].
3. Exponentiation Law:
- Use the property of exponents: [tex]\(i^3 = (i^2) \cdot i\)[/tex].
4. Calculate [tex]\(i^3\)[/tex]:
- Substitute [tex]\(i^2 = -1\)[/tex] into the expression for [tex]\(i^3\)[/tex]:
[tex]\[ i^3 = (i^2) \cdot i = (-1) \cdot i = -i \][/tex]
5. Imaginary Number Form:
- Writing in the form of complex numbers, where the real part is 0:
[tex]\[ -i = 0 - 1i \][/tex]
So, the calculations give us:
- [tex]\(i^2\)[/tex] is [tex]\(-1\)[/tex]
- [tex]\(i^3\)[/tex] is [tex]\(-i\)[/tex] or represented as [tex]\(0 - 1i\)[/tex].
Thus, we have:
[tex]\[ i^2 = -1 + 0j \][/tex]
[tex]\[ i^3 = -0 - 1j \][/tex]
These results match our understanding of the powers of the imaginary unit [tex]\(i\)[/tex].
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.