Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
To solve for [tex]\(i^3\)[/tex] using the properties of imaginary numbers and exponents, follow these steps:
1. Understanding [tex]\(i\)[/tex] and its powers:
- Recall that [tex]\(i\)[/tex] is the imaginary unit, defined by [tex]\(i^2 = -1\)[/tex].
2. Calculate [tex]\(i^2\)[/tex]:
- By definition, [tex]\(i^2 = -1\)[/tex].
3. Exponentiation Law:
- Use the property of exponents: [tex]\(i^3 = (i^2) \cdot i\)[/tex].
4. Calculate [tex]\(i^3\)[/tex]:
- Substitute [tex]\(i^2 = -1\)[/tex] into the expression for [tex]\(i^3\)[/tex]:
[tex]\[ i^3 = (i^2) \cdot i = (-1) \cdot i = -i \][/tex]
5. Imaginary Number Form:
- Writing in the form of complex numbers, where the real part is 0:
[tex]\[ -i = 0 - 1i \][/tex]
So, the calculations give us:
- [tex]\(i^2\)[/tex] is [tex]\(-1\)[/tex]
- [tex]\(i^3\)[/tex] is [tex]\(-i\)[/tex] or represented as [tex]\(0 - 1i\)[/tex].
Thus, we have:
[tex]\[ i^2 = -1 + 0j \][/tex]
[tex]\[ i^3 = -0 - 1j \][/tex]
These results match our understanding of the powers of the imaginary unit [tex]\(i\)[/tex].
1. Understanding [tex]\(i\)[/tex] and its powers:
- Recall that [tex]\(i\)[/tex] is the imaginary unit, defined by [tex]\(i^2 = -1\)[/tex].
2. Calculate [tex]\(i^2\)[/tex]:
- By definition, [tex]\(i^2 = -1\)[/tex].
3. Exponentiation Law:
- Use the property of exponents: [tex]\(i^3 = (i^2) \cdot i\)[/tex].
4. Calculate [tex]\(i^3\)[/tex]:
- Substitute [tex]\(i^2 = -1\)[/tex] into the expression for [tex]\(i^3\)[/tex]:
[tex]\[ i^3 = (i^2) \cdot i = (-1) \cdot i = -i \][/tex]
5. Imaginary Number Form:
- Writing in the form of complex numbers, where the real part is 0:
[tex]\[ -i = 0 - 1i \][/tex]
So, the calculations give us:
- [tex]\(i^2\)[/tex] is [tex]\(-1\)[/tex]
- [tex]\(i^3\)[/tex] is [tex]\(-i\)[/tex] or represented as [tex]\(0 - 1i\)[/tex].
Thus, we have:
[tex]\[ i^2 = -1 + 0j \][/tex]
[tex]\[ i^3 = -0 - 1j \][/tex]
These results match our understanding of the powers of the imaginary unit [tex]\(i\)[/tex].
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.