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Sagot :
To balance the chemical equation [tex]\(\text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{H}_2\text{O}_2 + \text{BaSO}_4\)[/tex], we must ensure that the number of each type of atom on the reactants side (left-hand side) is equal to the number on the products side (right-hand side). Here's the step-by-step solution:
1. Identify and write down the number of atoms for each element in the reactants and products:
Reactants:
- Ba (Barium): There is 1 atom of Ba in [tex]\(\text{BaO}_2\)[/tex].
- O (Oxygen): There are 2 atoms of O in [tex]\(\text{BaO}_2\)[/tex] and 4 atoms of O in [tex]\(\text{H}_2\text{SO}_4\)[/tex], totaling 6 atoms.
- H (Hydrogen): There are 2 atoms of H in [tex]\(\text{H}_2\text{SO}_4\)[/tex].
- S (Sulfur): There is 1 atom of S in [tex]\(\text{H}_2\text{SO}_4\)[/tex].
Products:
- Ba (Barium): There is 1 atom of Ba in [tex]\(\text{BaSO}_4\)[/tex].
- O (Oxygen): There are 2 atoms of O in [tex]\(\text{H}_2\text{O}_2\)[/tex] and 4 atoms of O in [tex]\(\text{BaSO}_4\)[/tex], totaling 6 atoms.
- H (Hydrogen): There are 2 atoms of H in [tex]\(\text{H}_2\text{O}_2\)[/tex].
- S (Sulfur): There is 1 atom of S in [tex]\(\text{BaSO}_4\)[/tex].
2. Compare the number of each type of atom on both sides for balance:
- Ba: 1 on both sides
- O: 6 on both sides
- H: 2 on both sides
- S: 1 on both sides
3. Determine the coefficients needed to balance the equation:
Since the number of each type of atom on both sides is already the same, the equation is balanced as is. Therefore:
[tex]\[ 1 \text{ BaO}_2 + 1 \text{ H}_2\text{SO}_4 \rightarrow 1 \text{ H}_2\text{O}_2 + 1 \text{ BaSO}_4 \][/tex]
The coefficients that balance the chemical equation are as follows:
[tex]\[ \checkmark \checkmark \text{1 BaO}_2 + \sim \sim \text{1 H}_2\text{SO}_4 \rightarrow (\sim) \text{1 H}_2\text{O}_2 + (\sim) \text{1 BaSO}_4 \][/tex]
So, the drop-down menu should look like this:
- For [tex]\(\text{BaO}_2\)[/tex], choose 1
- For [tex]\(\text{H}_2\text{SO}_4\)[/tex], choose 1
- For [tex]\(\text{H}_2\text{O}_2\)[/tex], choose 1
- For [tex]\(\text{BaSO}_4\)[/tex], choose 1
1. Identify and write down the number of atoms for each element in the reactants and products:
Reactants:
- Ba (Barium): There is 1 atom of Ba in [tex]\(\text{BaO}_2\)[/tex].
- O (Oxygen): There are 2 atoms of O in [tex]\(\text{BaO}_2\)[/tex] and 4 atoms of O in [tex]\(\text{H}_2\text{SO}_4\)[/tex], totaling 6 atoms.
- H (Hydrogen): There are 2 atoms of H in [tex]\(\text{H}_2\text{SO}_4\)[/tex].
- S (Sulfur): There is 1 atom of S in [tex]\(\text{H}_2\text{SO}_4\)[/tex].
Products:
- Ba (Barium): There is 1 atom of Ba in [tex]\(\text{BaSO}_4\)[/tex].
- O (Oxygen): There are 2 atoms of O in [tex]\(\text{H}_2\text{O}_2\)[/tex] and 4 atoms of O in [tex]\(\text{BaSO}_4\)[/tex], totaling 6 atoms.
- H (Hydrogen): There are 2 atoms of H in [tex]\(\text{H}_2\text{O}_2\)[/tex].
- S (Sulfur): There is 1 atom of S in [tex]\(\text{BaSO}_4\)[/tex].
2. Compare the number of each type of atom on both sides for balance:
- Ba: 1 on both sides
- O: 6 on both sides
- H: 2 on both sides
- S: 1 on both sides
3. Determine the coefficients needed to balance the equation:
Since the number of each type of atom on both sides is already the same, the equation is balanced as is. Therefore:
[tex]\[ 1 \text{ BaO}_2 + 1 \text{ H}_2\text{SO}_4 \rightarrow 1 \text{ H}_2\text{O}_2 + 1 \text{ BaSO}_4 \][/tex]
The coefficients that balance the chemical equation are as follows:
[tex]\[ \checkmark \checkmark \text{1 BaO}_2 + \sim \sim \text{1 H}_2\text{SO}_4 \rightarrow (\sim) \text{1 H}_2\text{O}_2 + (\sim) \text{1 BaSO}_4 \][/tex]
So, the drop-down menu should look like this:
- For [tex]\(\text{BaO}_2\)[/tex], choose 1
- For [tex]\(\text{H}_2\text{SO}_4\)[/tex], choose 1
- For [tex]\(\text{H}_2\text{O}_2\)[/tex], choose 1
- For [tex]\(\text{BaSO}_4\)[/tex], choose 1
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