Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer:
90 m
Explanation:
The rocket undergoes constant acceleration. We can use kinematic equations, also known as SUVAT equations, to model the rocket's motion. For this problem, we will use the following equations:
s = ut + ½ at²
v = u + at
v² = u² + 2as
where
- s is the displacement
- u is the initial velocity
- v is the final velocity
- a is the acceleration
- t is the time
During the first part of the rocket's motion, it starts from rest (u = 0) and accelerates upward at a = 10.0 m/s² for a time of t = 3.0 s. The displacement after this time is:
s = ut + ½ at²
s = (0) (3.0) + ½ (10.0) (3.0)²
s = 45 m
The velocity of the rocket after this time is:
v = u + at
v = 0 + (10.0) (3.0)
v = 30.0 m/s
Next, the rocket decelerates from this speed (u = 30.0 m/s) at a rate of a = -10.0 m/s² until it reaches a stop (v = 0 m/s). The displacement of the rocket at this point is:
v² = u² + 2as
(0)² = (30.0)² + 2 (-10.0) s
s = 45 m
The rocket travels up 45 meters during acceleration, then another 45 meters during deceleration. The total height reached is:
45 m + 45 m = 90 m
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.