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Sagot :
To determine the number of electrons in the sodium ion [tex]\(_{11}^{23} \text{Na}^{+}\)[/tex], follow these steps:
1. Understand the atomic number: Sodium (Na) has an atomic number of 11. This means a neutral sodium atom contains 11 protons and 11 electrons.
2. Identify the charge on the ion: The sodium ion in question is [tex]\(\text{Na}^{+}\)[/tex]. The positive charge ([tex]\(+\)[/tex]) indicates that the sodium atom has lost one electron.
3. Calculate the number of electrons in the ion:
- Start with the number of electrons in a neutral sodium atom: 11 electrons.
- Because the ion has a positive charge, it has lost one electron.
- Therefore, subtract one electron from the neutral atom's electron count: [tex]\(11 - 1 = 10\)[/tex] electrons.
Thus, the sodium ion [tex]\(_{11}^{23} \text{Na}^{+}\)[/tex] has 10 electrons.
So the correct answer is:
[tex]\[ \boxed{10} \][/tex]
1. Understand the atomic number: Sodium (Na) has an atomic number of 11. This means a neutral sodium atom contains 11 protons and 11 electrons.
2. Identify the charge on the ion: The sodium ion in question is [tex]\(\text{Na}^{+}\)[/tex]. The positive charge ([tex]\(+\)[/tex]) indicates that the sodium atom has lost one electron.
3. Calculate the number of electrons in the ion:
- Start with the number of electrons in a neutral sodium atom: 11 electrons.
- Because the ion has a positive charge, it has lost one electron.
- Therefore, subtract one electron from the neutral atom's electron count: [tex]\(11 - 1 = 10\)[/tex] electrons.
Thus, the sodium ion [tex]\(_{11}^{23} \text{Na}^{+}\)[/tex] has 10 electrons.
So the correct answer is:
[tex]\[ \boxed{10} \][/tex]
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