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Lucy bought some books for [tex]$3$[/tex] each and received a discount of [tex]$6$[/tex] off of her total purchase. She spent [tex]$45$[/tex] after the discount. How many books did she buy?

(a) Write an equation that could be used to answer the question above. First, choose the appropriate form. Then, fill in the blanks with the numbers 3, 6, and 45. Let [tex]$b$[/tex] represent the number of books.

[tex]\[ 3b - 6 = 45 \][/tex]

(b) Solve the equation in part (a) to find the number of books.

[tex]\[ b = \][/tex]

Sagot :

To solve the problem, we need to create an equation that represents the situation and then solve it step-by-step.

(a) We need to formulate the equation based on the given information:

1. The cost of each book is [tex]$3. 2. Lucy receives a discount of $[/tex]6 off her total purchase.
3. After the discount, she spent [tex]$45. Let \( b \) represent the number of books Lucy bought. The total cost before the discount would be \( 3b \) because each book costs $[/tex]3 and she bought [tex]\( b \)[/tex] books. After applying the discount of [tex]$6, the total cost is reduced to $[/tex]45. Therefore, we can write the equation:

[tex]\[ 3b - 6 = 45 \][/tex]

(b) Now, let's solve the equation to find the number of books [tex]\( b \)[/tex].

1. Start with the equation:

[tex]\[ 3b - 6 = 45 \][/tex]

2. Add 6 to both sides of the equation to isolate the term with [tex]\( b \)[/tex] on one side:

[tex]\[ 3b - 6 + 6 = 45 + 6 \][/tex]

This simplifies to:

[tex]\[ 3b = 51 \][/tex]

3. Divide both sides of the equation by 3 to solve for [tex]\( b \)[/tex]:

[tex]\[ \frac{3b}{3} = \frac{51}{3} \][/tex]

This simplifies to:

[tex]\[ b = 17 \][/tex]

So, Lucy bought [tex]\( 17 \)[/tex] books.