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1. Determine Molar Mass of HCl:
- The molar mass of hydrogen (H) is 1 g/mol.
- The molar mass of chlorine (Cl) is 35.5 g/mol.
- Thus, the molar mass of HCl (H + Cl) is [tex]\(1 + 35.5 = 36.5\)[/tex] g/mol.
2. Calculate Moles of HCl:
- Given mass of HCl is 45 grams.
- To find the number of moles, we use the formula:
[tex]\[ \text{moles\_HCl} = \frac{\text{mass\_HCl}}{\text{molar\_mass\_HCl}} \][/tex]
- Substituting the values, we get:
[tex]\[ \text{moles\_HCl} = \frac{45}{36.5} \approx 1.2329 \text{ moles} \][/tex]
3. Calculate Volume of Solution:
- Molarity (M) is defined as the number of moles of solute per liter of solution.
- We know the molarity ([tex]\( M \)[/tex]) and the moles of HCl.
- We use the formula:
[tex]\[ \text{Volume of solution (L)} = \frac{\text{moles\_HCl}}{\text{Molarity}} \][/tex]
- Substituting the values, we get:
[tex]\[ \text{Volume of solution} = \frac{1.2329}{1.5} \approx 0.8219 \text{ liters} \][/tex]
Therefore, to make a 1.5 M solution of HCl using 45 grams of HCl, you would need approximately 0.8219 liters of solution.
1. Determine Molar Mass of HCl:
- The molar mass of hydrogen (H) is 1 g/mol.
- The molar mass of chlorine (Cl) is 35.5 g/mol.
- Thus, the molar mass of HCl (H + Cl) is [tex]\(1 + 35.5 = 36.5\)[/tex] g/mol.
2. Calculate Moles of HCl:
- Given mass of HCl is 45 grams.
- To find the number of moles, we use the formula:
[tex]\[ \text{moles\_HCl} = \frac{\text{mass\_HCl}}{\text{molar\_mass\_HCl}} \][/tex]
- Substituting the values, we get:
[tex]\[ \text{moles\_HCl} = \frac{45}{36.5} \approx 1.2329 \text{ moles} \][/tex]
3. Calculate Volume of Solution:
- Molarity (M) is defined as the number of moles of solute per liter of solution.
- We know the molarity ([tex]\( M \)[/tex]) and the moles of HCl.
- We use the formula:
[tex]\[ \text{Volume of solution (L)} = \frac{\text{moles\_HCl}}{\text{Molarity}} \][/tex]
- Substituting the values, we get:
[tex]\[ \text{Volume of solution} = \frac{1.2329}{1.5} \approx 0.8219 \text{ liters} \][/tex]
Therefore, to make a 1.5 M solution of HCl using 45 grams of HCl, you would need approximately 0.8219 liters of solution.
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