To determine the product of the reaction between sodium phosphate ([tex]$NaPO_3$[/tex]) and copper(II) oxide ([tex]$CuO$[/tex]), let's carefully consider the reactants and predict the reaction products.
### Step-by-Step Analysis
1. Identify Reactants:
- Sodium phosphate ([tex]$NaPO_3$[/tex])
- Copper(II) oxide ([tex]$CuO$[/tex])
2. Determine the Type of Reaction:
This is a double displacement reaction (also known as a metathesis reaction), where the cations and anions of two different compounds switch places to form two entirely new compounds.
3. Predict Possible Products:
- When [tex]$NaPO_3$[/tex] and [tex]$CuO$[/tex] react, the sodium ion ([tex]$Na^+$[/tex]) could pair with the phosphate group ([tex]$PO_4^{3-}$[/tex]) from the sodium phosphate, and the copper ion ([tex]$Cu^{2+}$[/tex]) could pair with the remaining components.
4. Write the Potential Balanced Reaction:
We seek the most chemically reasonable and balanced compound. Given the ions involved:
- One likely product of this reaction is [tex]$NaCuPO_4$[/tex], where [tex]$Na^+$[/tex] from sodium phosphate and [tex]$Cu^{2+}$[/tex] from copper oxide combine with the phosphate group ([tex]$PO_4^{3-}$[/tex]).
5. Evaluate the Given Options:
- [tex]$NaO + CuPO_3$[/tex]: This option doesn't make much sense as these compounds are not typical products of such a reaction.
- [tex]$Na + P + Cu + O_4$[/tex]: This option is highly unlikely as these are elementary substances.
- [tex]$NaCuPO_4$[/tex]: This option is chemically feasible and likely to form as a result of the reaction.
- [tex]$NaCu + PO_4$[/tex]: This product is unrealistic as [tex]$NaCu$[/tex] (an alloy) would not form in such a reaction, and [tex]$PO_4$[/tex] would not exist free.
### Conclusion
The most likely product of the reaction between sodium phosphate ([tex]$NaPO_3$[/tex]) and copper(II) oxide ([tex]$CuO$[/tex]) is [tex]$NaCuPO_4$[/tex].
Thus, the correct answer is:
[tex]$ \boxed{NaCuPO_4} $[/tex]
